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dolphi86 [110]
4 years ago
11

A retail store has three departments, S, T, and U, and does general advertising that benefits all departments. Advertising expen

se totaled $50,000 for the year, and departmental sales were as follows. Allocate advertising expense to Department T based on departmental sales. Department S $ 110,000 Department T 213,750 Department U 151,250 Total $ 475,000 Multiple Choice $11,000. $14,000. $16,667. $22,500. $50,000.
Business
1 answer:
Andrew [12]4 years ago
8 0

Answer: $22,500

Explanation:

First calculate the rate of allocation based on sales to determine how much of Department T's sales should be attributed to Advertising.

The Rate of Allocation based on Sales = Advertising Expense/Total sales

= 50,000/475,000

= 0.105263

= 10.5263%

This 10.5% can then be used to find out how much of Advertising to apportion to Department T based on department sales,

= Department sales * Allocation rate

= 213,750 * 10.5263%

= $22,500

$22,500 should be allocated to Department T.

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Answer:

Original Sale Price = $6000

Explanation:

Lets say that the original Sale price is 100%. When the first discount is offered, the car is discounted by 10% and offered for 90% of the original price.

The second discount is offered as 20% off from the discounted sale price. Thus the car is now offered at,

Price after Second Discount = 90% * (1 - 20%)  =  72% of the original price

Now the final discount is offered as further 25% off from the Second Discounted price which is already 72% of the original price. Thus the price after final discount will be,

Price after final discount = 72% * (1 - 25%)  =  54% of the original price

We know the price after final discount is 54% of the original price and we are provided the amount as 3240. Thus if 54% of original price is 3240, then the original price will be,

Original Sale Price = 3240 * 100%/54%

Original Sale Price = $6000

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3 years ago
If the processor has forwarding, but we forgot to implement the hazard detection unit, what happens when this code executes?
Solnce55 [7]

If the processor has forwarding, but you forgot to implement the hazard detection unit and when the code executes, you need to control the signal. It is the signal that informs the new ALU. You should also perform the execution of the given codes.

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5 0
4 years ago
Which rule of evidence would an attorney break if he or she were to ask a witness what rumors were being spread about the defend
IgorLugansk [536]
The r<span>ule of evidence would an attorney break if he or she were to ask a witness what rumors were being spread about the defendant is hearsay. Hearsay is the report from another person's words by the witness, usually disallowed in a court of law. </span>
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3 years ago
Humbert believes that he is in control of his own destiny. If he works hard and keeps on working hard, he will be able to overco
kolezko [41]
<h2>Humbert <u>High internal </u>locus of control</h2>

Explanation:

Let us understand the term internal locus of control.

Internal locus is having a high belief on oneself. The term can be explained in deeper saying, a person belief himself that he is sole responsible for the result which is derived from his own action.

For eg:

Every person would be expecting his school results. So depending on the result like pass or fail, a person with high internal locus believe that, he has done well so he got pass, or he has not prepared properly so he failed.

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4 years ago
A popular soft drink is sold in 2​-liter ​(​2000-milliliter) bottles. Because of variation in the filling​ process, bottles have
saul85 [17]

Answer:

The answer is below.

Explanation:

The z score is a used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma}\\\\where\ x=raw\ score, \mu=mean,\sigma=standard\ deviation\\\\For\ a\ sample\ size(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

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For x < 1995 millimeters:

z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{1995-2000}{18/\sqrt{100} }  =-2.78

From the normal distribution table, P(x < 1995) = P(z < -2.78) = 0.0027

b) P(z > z*)  = 10% = 0.1

P(z < z*) = 1 - 0.1 = 0.9

z* = 1.28

z*=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\1.28=\frac{x-2000}{18/\sqrt{100} }\\\\x-2000  =-2.304\\\\x=2002.3\ ml\\\\

From the normal distribution table, P(z < z

6 0
3 years ago
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