Answer:
2 hours
Step-by-step explanation:
Mike has a six hour head start so he is 6 x 2 = 12 miles ahead
their 'closing speed' is 8-2 = 6 m/hr
it will take Kim 12 / 6 = two hours to catch Mike
Answer:
Step-by-step explanation:
![(4\sqrt{81})^{6} = (4*\sqrt{9*9} )^{6}\\\\=(4*9)^{6}\\\\=(2^{2}*3^{2})^{6}\\\\=[(2*3)^{2}]^{6}\\\\=(6)^{2*6}\\\\=6^{12}](https://tex.z-dn.net/?f=%284%5Csqrt%7B81%7D%29%5E%7B6%7D%20%20%3D%20%284%2A%5Csqrt%7B9%2A9%7D%20%29%5E%7B6%7D%5C%5C%5C%5C%3D%284%2A9%29%5E%7B6%7D%5C%5C%5C%5C%3D%282%5E%7B2%7D%2A3%5E%7B2%7D%29%5E%7B6%7D%5C%5C%5C%5C%3D%5B%282%2A3%29%5E%7B2%7D%5D%5E%7B6%7D%5C%5C%5C%5C%3D%286%29%5E%7B2%2A6%7D%5C%5C%5C%5C%3D6%5E%7B12%7D)
Exponent Laws:

The vertices of the feasible region are: (0, 0), (0, 3), (1.5, 3.5), (5, 0)
For (0, 0): C = 6(0) - 4(0) = 0
For (0, 3): C = 6(0) - 4(3) = -12
For (1.5, 3.5): C = 6(1.5) - 4(3.5) = 9 - 14 = -5
For (5, 0): C = 6(5) - 4(0) = 30
Therefore, the maximum value of the ob jective function is 30.