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3 years ago

Write the radical equation that has a flip/reflection over the x-axis and a vertical shift down 1.

Mathematics

1 answer:

yan [13]3 years ago

6 0

Answer:

lolidk

Step-by-step explanation:

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Please help !!

shutvik [7]

Given:

The limit problem is:

$\lim_{x\to 3}(x^2+8x-2)$

To find:

The limit of the function by using direct substitution.

Solution:

We have,

$\lim_{x\to 3}(x^2+8x-2)$

Applying limit, we get

$\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2$

$\lim_{x\to 3}(x^2+8x-2)=9+24-2$

$\lim_{x\to 3}(x^2+8x-2)=33-2$

$\lim_{x\to 3}(x^2+8x-2)=31$

Therefore, the correct option is D.

4 0

3 years ago

A person wants to create a vegetable garden and keeps the rabbits out by enclosing it with 100 feet of fencing. The area of the

alekssr [168]

Answer:

The garden can not have area of 700ft^2

Step-by-step explanation:

We are given equation for area as

$A(w)=w\times (50-w)$

where

w is the width (in feet) of the garden

now, we are given area =700 ft^2

so, we can set area =700

and then we can solve for w

$w\times (50-w)=700$

$50w-w^2=700$

$-w^2+50w-700=0$

now, we can use quadratic formula

$ax^2+bx+c=0$

$w=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

we can compare and find a,b, and c

a=-1 , b=50 , c=-700

now, we can plug values

$w=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-700\right)}}{2\left(-1\right)}$

$w=25-5\sqrt{3}i,\:w=25+5\sqrt{3}i$

We can see that values of w is not real

so, w does not exists when area =700

so, The garden can not have area of 700ft^2

4 0

3 years ago

keeping in mind the role the order of precedence plays in equations, what would excel display as the result of the following equ

Alex73 [517]

The answer to youre question is 5.5

8 0

3 years ago

How to solve it this equation

Stells [14]

You will divide eveything by 6
you will end up with
$n^2-3-4 \\
(n -4) (n-1) \\
n = 4 \\
and \\
n = 1$

5 0

3 years ago

Need help please answer asap

Vikki [24]

Answer:

$2x = x + 15$

Step-by-step explanation:

Angle AGH and GHD are corresponding angles, meaning they are equal. So in order to find the equation that can be used to solve for x we need to equate both angles AGH and GHD to each other.

$m < AGH\: \: \: = \: \: \: m < GHD \\ (x + 15) = (2x) \\ 15 = 2x - x \\ 15 = 1x \\ 15 = x$

They did not ask us to solve for x but I did it in case, however we can see that the answer we got corresponds with

$(1) \:2x = x + 15$

4 0

2 years ago

Read 2 more answers