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raketka [301]
3 years ago
15

What is 3/5 written as a decimal?

Mathematics
2 answers:
NARA [144]3 years ago
6 0

0.60 is the decimal for 3/5

iVinArrow [24]3 years ago
5 0

Answer:

0.6 I really hope this helped



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The answer to this is .75 seconds.


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During a food drive, a local middle school collected 8,887 canned food items. Each of the 27 classrooms that participated in the
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A triangle with vertices at A(0,0), B(0,4), and C(6,0) is dilated to yield a triangle with vertices at A(0,0), (B(0,10), and C (
dezoksy [38]

The required scale factor for the dialed triangle is given by SF= 6.28

A triangle with vertices at A(0,0), B(0,4), and C(6,0) is dilated to yield a triangle with vertices at A(0,0), (B(0,10), and C (C(15,0).

<h3>What is scale factor?</h3>

The scale factor is defined as the ratio of modified change in length to the original length.

Since, the height and base of the triangle is y coordinate of B and x coordinate of c is given by 4, 6
Area of triangle =1/2(base x height)
                         = 1/2 (4 x 6)
                         =   4.8
Similarly, for dilated triangle
Area of dilated triangle =  30

Now, scale factor(SF) = area of dilated triangle \ area of triangle
SF = 30/4.8
SF = 6.25

Thus, the required scale factor is SF = 6.25

 

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2 years ago
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Set the function equal to 2065 and solve for g, then that answer is how many games he played
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A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first r
Kryger [21]

The probability of occurrence for the events A, B and C is; 1/4.

<h3>What is the probability of occurrence of.the described events?</h3>

For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;

Event A = 2/8 = 1/4.

For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;

Event B = 2/8 = 1/4.

For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;

Event C = 2/8 = 1/4.

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