A is the answer. The graph shows a decrease i the value as age increases.
Hope this helps!!! :-)
Question:
1. The females worked less than the males, and the female median is close to Q1.
2. There is a high data value that causes the data set to be asymmetrical for the males.
3. There are significant outliers at the high ends of both the males and the females.
4. Both graphs have the required quartiles.
Answer:
The correct option is;
1. The females worked less than the males, and the female median is close to Q1
Step-by-step explanation:
Based on the given data, we have;
For males
Minimum = 0
Q1 = 1
Median or Q2 = 20
Q3 = 25
Maximum = 50
For females;
Minimum = 0
Q1 = 5
Median or Q2 = 6
Q3 = 10
Maximum = 18
Therefore, the values of data that affect the statistical measures of spread and center are that
The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range
Also the female median is very close to Q1, therefore it affects the definition of a measure of center.
Answer:
It is an enlargement because k=3 is larger than 1. Anything that equals less than one (ex. k=0.25) would be a reduction.
Step-by-step explanation:
The kite is symmetric about line segment BD.
Therefore
AB = BC
3x + 1 = 22
3x = 22 - 1 = 21
x = 21/3 = 7
Similarly,
AD = CD by symmetry
Therefore
4x = CD
4*7 = CD
28 = CD, the required line segment
Answer: 28
Answer:
The percent of change is 22.22%.
Step-by-step explanation:
You can calculate the percent of change by subtracting the original number from the final number and dividing that by the original number. Then, you have to multiply the result for 100:
percent of change=((1,100-900)/900)*100
percent of change=(200/900)*100
percent of change=22.22%
According to this, the answer is that the percent of change is 22.22%.
