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Sunny_sXe [5.5K]
3 years ago
5

You start driving north for 3 miles, turn right, and drive east for another 4 miles. At

Mathematics
1 answer:
Elanso [62]3 years ago
7 0

Answer:

The straight line distance is 5 miles from starting point

Step-by-step explanation:

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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
Subtract 7x^2−5xy+8y2 from −2x^2−15xy+9y^2
Digiron [165]

Answer

Subtract 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2

then;

-2x^2 -15xy+9y^2 - (7x^2 -5xy+8y^2)

Remove the bracket we have;

-2x^2 -15xy+9y^2 - 7x^2 + 5xy - 8y^2

Like terms are those terms which have same variable to the same power.

Combine like terms;

-9x^2 -10xy+y^2

Therefore, Subtracting 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2 we get -9x^2 -10xy+y^2

7 0
3 years ago
What is the derivative of y=(4x+1)(1-x)^3
Rudik [331]
I am not so sure of this but I feel it would serve as hint

6 0
4 years ago
How many qt equal to 5 gal
Naily [24]
20 quarts equal 5 gallons. There are 4 quarts in a gallon so:


4 x 5 = 20
7 0
3 years ago
Which expression represents a number, p, added to the difference of 25 and 5?
blsea [12.9K]
A, it correctly shows p added to 25-5.
3 0
3 years ago
Read 2 more answers
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