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Tanzania [10]
3 years ago
7

Find the HCF of 126 and 420

Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

Answer:

42

Step-by-step explanation:

Find the prime factorization of 126

126 = 2 × 3 × 3 × 7

Find the prime factorization of 420

420 = 2 × 2 × 3 × 5 × 7

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 3 × 7

GCF = 42

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Sergio [31]

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Answer:

  d)  -4 ≤ x ≤ 1.5

Step-by-step explanation:

The domain is the horizontal extent of the graph. Here, it goes from about x=-4 to about x = 1.5.

There are solid dots on both ends of the line segment, so the inequality will use ≤ for both limits. The domain is ...

  -4 ≤ x ≤ 1.5

6 0
3 years ago
Anyone know this answer for this question
svlad2 [7]

Answer:

What's the question, it's bloked on my computer

Step-by-step explanation:

3 0
3 years ago
cho hàm số y = f(x) có đạo hàm liên tục trên R thỏa mãn 2f(2x)+f(1-2x) = 12x2 víu mọi x thuộc R . Phương trình tiếp tuyến của đồ
Nina [5.8K]

Answer:

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Step-by-step explanation:

then I can help u

6 0
3 years ago
A pitcher holds 3/4 gallons of kool-aid. Martin wants to pour equal amounts of kool- aid into 6 smaller cotainers. How much kool
statuscvo [17]

Answer:

\dfrac{1}{8}\ gallons

Step-by-step explanation:

Amount of kool - aid that the pitcher can hold = \frac{3}4 gallons

There are 6 smaller containers in which this kool - aid is to be adjusted.

Also, the volume of the smaller containers is equal to each other i.e. the containers are identical to each other in terms of volume.

To find:

The amount of kool - aid that each container can hold?

Solution:

Volume of all the smaller containers combined = Volume of the kool - aid available

Let the volume of one smaller container = V

V + V + V + V + V + V = \dfrac{3}{4}\ gallons

\Rightarrow 6V = \dfrac{3}{4}\ gallons\\\Rightarrow V = \dfrac{3}{4\times 6 }\ gallons\\\Rightarrow V=\bold{\dfrac{1}{8}\ gallons}

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8 0
3 years ago
What is the unit's digit of 3127 to the power of 173
bulgar [2K]
3127^173 ≡ 7^173 mod 10

Now - let's look at the powers of 7 mod 10:

7^1 = 7 mod 10
7^2 = 49 ≡ 9 mod 10
7^3 ≡ 3 mod 10
7^4 ≡ 1 mod 10

And this cycle repeats. So

7^173 ≡ 7^1 ≡ 7 mod 10

The last digit is 7.
8 0
3 years ago
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