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ad-work [718]
3 years ago
13

What is the solution to -3/4x

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

3x/4

Step-by-step explanation:

that's what I found. It would be better if u had more details in your question.

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At a coffee shop, the first 100 customers'
Paladinen [302]

\frac{1}{5}

Step-by-step explanation:

cold =25

large=5

\frac{5}{25}

divide it

\frac{1 }{5}

8 0
2 years ago
There were 230 shoppers at an electronics store on opening day. The specials that day allowed 21​% of shoppers to receive a free
anastassius [24]

Answer:

a) About 48 of the shoppers, that is 230\frac{21}{100} of the shoppers, received a free set of​ earbuds.

b) About 58 shoppers, that is \frac{230}{4} received ​$5 off their first​ purchase.

Step-by-step explanation:

a. About how many shoppers received a free set of​ earbuds?

21% out of 230. So

230\frac{21}{100} = 2.3(21) = 48.3

About 48 of the shoppers, that is 230\frac{21}{100} of the shoppers, received a free set of​ earbuds.

b. About how many shoppers received ​$5 off their first​ purchase?

25% out of 230, so:

230\frac{25}{100} = 230\frac{1}{4} = \frac{230}{4} = 57.5

About 58 shoppers, that is \frac{230}{4} received ​$5 off their first​ purchase.

5 0
3 years ago
The ordered pair R(-2, 7) is translated 5 units to the right and 2 units down.
Usimov [2.4K]
Left and right affect domain. (x)

Up and down effects range. (y)

So,

-2+5 (because the right of the number line is an increase)

7-2 (because you are decreasing by going down)

You are left with:

R'(3,5)

I hope this helps!
~cupcake
8 0
3 years ago
Is this correct? If not<br> please tell me the answer!
attashe74 [19]
Yes, you are absolutely correct.
3 0
3 years ago
On the first part of her trip Natalie rode her bike 16 miles and on the second part of the trip she rode her bike 42 miles. Her
-BARSIC- [3]

Answer:

14 mph   ( average speed during the second part of the trip )

Step-by-step explanation:

Let´s call  "x"  the average speed during the first part then

t = 5 hours

t  =  t₁  +  t₂        t₁   and  t₂   times during part 1 and 2 respectively

l = t*v           (  distance is speed by time )      t =  l/v

First part

t₁  = 16/x        and      t₂  = 42 / ( x + 6)

Then

t =   5   =  16/x   +   42 /(x + 6)

5 = [ 16 * ( x  +  6 ) +  42 * x ] / x* ( x + 6 )

5 *x * ( x + 6 )  =  16*x  + 96 +  42 x

5*x² + 30*x  - 58*x - 96  =  0

5*x²  -  28*x  -  96  =  0

We obtained a second degree equation, we will solve for x and dismiss any negative root since negative time has not sense

x₁,₂  =   [28 ± √ (28)² + 1920  ] / 10

x₁,₂  = ( 28  ± √2704 )/ 10

x₁  = 28  -  52 /10        we dismiss that root

x₂  = 80/10

x₂  =  8 mph       average speed during the first part, and the average speed in the second part was 6 more miles than in the firsst part. then the average spedd dring the scond part was 8 + 6 = 14 mph

6 0
4 years ago
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