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jeka94
2 years ago
15

First, rewrite 9/10 and 23/25 so that they have a common denominator.

Mathematics
2 answers:
Vlad1618 [11]2 years ago
5 0
The lowest common multiple of 10 and 25 is 50, so set that as the denominator.

9/10=45/50 (multiply by 5)
23/25=46/50 (multiply by 2)

46/50 > 45/50 therefore
23/25 > 9/10.

Hope this helps :)
MAVERICK [17]2 years ago
3 0
The cheap answer is, well, all we do is, grab the denominator of one and multiply the other by it, top and bottom, and grab the denominator of the other, and multiply the first one by that one too, that way, both will have the same denominator, and then you can simply check the numerator to see who's larger, let's do so.

\bf \cfrac{9}{\boxed{10}}\qquad \qquad \cfrac{23}{\boxed{25}}
\\\\\\
\cfrac{9\cdot \boxed{25}}{10\cdot \boxed{25}}\implies \cfrac{225}{250}\qquad \qquad \qquad \cfrac{23\boxed{10}}{25\cdot \boxed{10}}\implies \cfrac{230}{250}\\\\
-------------------------------\\\\
\textit{so, which is larger then?}\qquad \cfrac{225}{250}~or~\cfrac{230}{250}?

surely you can tell.
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Question 7 Daurie rides on her motorcycle for 252 miles on 6 gallons of gas. At this rate, how far will she get on 2 gallons of
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3 years ago
I don’t get this T-chart
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A baseball is hit and its height is given by h = 29.4t – 4. 9t^2, where h is the
ioda

Answer:

44.1m

Step-by-step explanation:

we are given a quadratic function which represents the height and time of a baseball

\displaystyle h = 29.4t - 4.9 {t}^{2}

we want to figure out maximum height of

the baseball

since the given function is a quadratic function so we have a parabola

which means figuring out the maximum height is the same thing as figuring out the maximum y coordinate (vertex)

to do so we can use some special formulas

recall that,

\displaystyle \rm t= \frac{ - b}{  2a}

\displaystyle H_{\text{max}}=f(t)

notice that, our given function is not in standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

let's make it so

\displaystyle h =  - 4.9 {t}^{2}  + 29.4t

therefore we got

our <em>a</em> is -4.9 and <em>b </em>is 29.4

so substitute:

\displaystyle\rm t=  \frac{ -( 29.4)}{  2 \cdot - 4.9}

remove parentheses and change its sign:

\displaystyle\rm t=  \frac{ -29.4}{  2 \cdot - 4.9}

simplify multiplication:

\displaystyle\rm t=  \frac{ -29.4}{  - 9.8}

simplify division:

\displaystyle  \: t  = 3

so we have figured out the time when the baseball will reach the maximum height

now we have to figure out the height

to do so

substitute the got value of time to our given function

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot {3}^2

simplify square:

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot 9

simplify mutilation:

\displaystyle H_{\text{max}}=88.2-44.1

simplify substraction:

\displaystyle H_{\text{max}}=44.1

hence,

the maximum height of the baseball is 44.1 metres

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3 years ago
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