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3 years ago

Solve the system of equations by substitution 5x +y = 36 y = 4x

Mathematics

2 answers:

natali 33 [55]3 years ago

7 0

Step-by-step explanation:

The answer is mentioned above.

Eduardwww [97]3 years ago

3 0

To start off your going to plug in 4x into the equation. Which will turn into 5x + 4x = 36. You will add 5 and 4 since they both have an x in it. Which would leave you to 9x = 36. Only thing left to do is divide 36 by 9. Which would equal to 4 and that will be your answer. X=4

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2/7 - 3/2 for anyone that doesant know that’s a fraction am struggling on

enyata [817]

Answer:

-17/14

Step-by-step explanation:

To subtract fractions, you must have a common denominator. If that is not given, you make it.

You do so buy finding the LCM of denominators:

LCM of 7 and 2 = 14

Now, here you have multiplied the denominators either by 7 or 2. You do the same for the respective numerators:

2x2/14 - 3x7/14 = 4/14 - 21/14.

Now that you have the same denominator, subtract the numerators:

4-21 = - 17

Put it back as a fraction : -17/14

hope this helps.

7 0

2 years ago

What is 4^ -3 4^ -2 2^ -3 + 3 2^ -2 +3 2^ -1 + 3

Scrat [10]

1/4³ or 1/64
1/4² or 1/16
1/2³ + 3 or 3 1/8 or 3.125
1/2²+3 or 1/4 +3 or 3 1/4 or 3.25
1/2¹ +3 or 3 1/2 or 3.5

6 0

2 years ago

Please help me do it

GREYUIT [131]

4x+1=5x-5
6=x
This is because you subtract 4x from 5x and get 1x and add the -5 to the other side

8 0

2 years ago

Log base 6 (2x+1) = log base 6 (x-3) + log base 6 (x+5)

spin [16.1K]

We assume you want to find values of x that make the expression true.

Use the rules of logarithms to rewrite as a single log. Then take the antilog and solve the resulting quadratic.

$\log_{6}(2x+1)=\log_{6}(x-3)+\log_{6}(x+5)=\log_{6}((x-3)(x+5))\\\\2x+1=(x-3)(x+5)=x^{2}+2x-15\\\\0=x^{2}-16=(x-4)(x+4)$

The term $\log_{6}(x-3)$ is only defined for x > 3, so the only solution to this equation is x = 4.

8 0

3 years ago

Please help Solve the equation. 5|x-3|=15

Vlad1618 [11]

Answer:

x=6 or x=0

Step-by-step explanation:

$5 |x - 3| = 15$

$|x - 3| = 3$

$x - 3 = 3$

$x - 3 = - 3$

4 0

2 years ago