Yes that is correct ma dude
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
I’m going to go with 77 i’m pretty sure
49,000 is the nearest round to the hundredth to 48,950
Answer:
0+100 1+1000 2+2000 3+3000
Step-by-step explanation:
