Answer:
it's helps it by standing
Answer:
1. (7,-9)
2. (4,0) and (10,0)
3. (3,0) and (-3,0)
4. (0,-9)
5. (-1,-32)
Step-by-step explanation:
To find the vertex use the formula

First make the equation into a quadratic equation.

Now it is in the form

Now we can substitute the values

Now we have 7 as our x value for the vertex we can substitute for y,

So the vertex for 1 is (7,-9)
To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.

4 is slightly different but start the same,

Here, c (9) just shows the graph move down 9, so the y intercept = 9.
5 is the same process as 1,

Vertex,

Substitute,

So the vertex is (-1,-32)

Let's solve ~
Here, 6x is present on both the sides of equation so they cancel out ~ therefore there is no one solution satisfying the equation ~
Answer:
13
Step-by-step explanation:
2x+2-3x-15>0
-x+13>0
-x>0-13
x>-13/-1
x>13