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4 years ago

Write the equation in slope-intercept form: 4x - 2y = 12

Mathematics

2 answers:

asambeis [7]4 years ago

7 0

6-4/2x=y

Hope this helps and pls tell me if im right

Licemer1 [7]4 years ago

6 0

The equation 4x-2y=12 written in slope intercept form is y=-2x+6

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determine the diameter to the nearest inch of a large can of tuna that has a volume 6068 inches and a height of 3.3 inches

anyanavicka [17]

Answer:

The diameter of can is 48 inches.

Step-by-step explanation:

Given:

Volume of can = 6068 inches.

And height(h) = 3.3 inches.

Now, to find the diameter.

Diameter = 2 × radius

Let radius be $r.$

So, by putting the formula of volume we get the radius:

$Volume =\pi r^2h$

$6068=3.14\times r^2\times 3.3$ (taking the value of π=3.14)

$6068=10.362\times r^2$

Dividing both sides by 10.362 we get:

$585.60=r^2$

Using square root on both sides we get:

$24.199=r$

Radius = 24.199 inches.

Then, we get the diameter:

Diameter = 2 × radius

Diameter = 2 × 24.199 = 48.398 inches.

Diameter = 48 inches (rounding to nearest, inch as in the place of tenth it is 3 which is less than 5.)

Therefore, the diameter of can is 48 inches.

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3 years ago

How many 2-letter combinations can be made from the letters A, B, C, and D?

yulyashka [42]

Answer:

Step-by-step explanation:

each letter can be used with each other 3 times and there are 4 letters so 12

5 0

3 years ago

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yKpoI14uk [10]

Answer:

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3 years ago

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Factor the expression. 3x + 21

Delicious77 [7]

Answer: 3 ( x + 7 )

Step-by-step explanation:

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3 years ago

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A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th

Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

$\tan\theta=\frac{Perpendicular}{base}$

Here, $\theta=11.1^{\circ}$ ,Perpendicular AB = 4000

$\tan\theta=\frac{AB}{BC}$

$\tan 11.1^{\circ} =\frac{4000}{BC}$

Solving for BC, we get,

$BC=\frac{4000}{\tan 11.1^{\circ} }$

$BC=\frac{4000}{0.196}$ (approx)

$BC=20408.16$ (approx)

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0

3 years ago