We will call an adult ticket <em>a</em>, and a child ticket <em>c</em>.
Since they sold 60 tickets in total, we can form the equation:
a + c = 60
We can also say that the sum of money from the adult tickets and child tickets combined is 460.
Thus we can say
11a + 6c = 460
Now, we must solve our system.
a + c = 60
11a + 6c = 460
6a + 6c = 360
11a + 6c = 460
-5a = -100
a = 20
Thus, (20) + c = 60
c = 40
a = 20 and c = 40
D, as a frame goes around the entire photo, so having the perimeter would show the length of wood needed to surround the photo.
1/3 is 0.3333333 and you round it by the 3rd three, so it looks like 0.334
Cross multiply.
5.4x=9*25.8
5.4x=232.2 Divide both sides by 5.4
x=43
It is more than just a quadrilateral. In fact it is going to be hard to pick.
These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.
The converse is "If you have a parallelagram, the diagonals bisect each other."
You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.
