All categories

3 years ago

Dan is framing a picture of his baseball team.

1 answer:

katrin2010 [14]3 years ago

7 0

D, as a frame goes around the entire photo, so having the perimeter would show the length of wood needed to surround the photo.

You might be interested in

Adalyn has a silver bracelet that is made from 1.7 g of copper and 22.3 g of silver.

vodka [1.7K]

1.7 : 22.3
17 : 223 is the ratio. Times 10 throughout

6 0

3 years ago

In 1912, the U.S. government began issuing licenses to radio stations. Each station was given a unique three-letter call sign. R

tatuchka [14]

Answer:

A would make sense

Step-by-step explanation:

6 0

3 years ago

Trey’s desk is 3 feet wide. How many inches wide is the desk? A:3 inches B:24 inches C:36 inches or D: 48 inches

natali 33 [55]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can you help me fill in the blanks?

Pepsi [2]

10 pints = 5 quarts

4 pints = 2 quarts

6 pints = 3 quarts

2 pints = 1 quart

The Bold numbers are the ones you need to fill in.

Hope that helps :D

8 0

3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago