All categories

3 years ago

If both diagonals of a quadrilateral bisect each other when is the quadrilateral a parallelogram?

1 answer:

6 0

It is more than just a quadrilateral. In fact it is going to be hard to pick.

These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.

The converse is "If you have a parallelagram, the diagonals bisect each other."

You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.

You might be interested in

What are the solutions to the equation 0 = x2 - x-6? Select two options

gregori [183]

Answer:

x=3, x=-2

Step-by-step explanation:

If this equation is $x^2-x-6$ , then plug in each number. For this example, I'll only do the correct answers.

$3^2=9\\9-3-6=0$

$-2^2=4\\4-(-2)-6=0\\or\\4+2-6=0$

Hope this helps!

4 0

3 years ago

Read 2 more answers

Two soccer teams play 8 games in their season. The number of goals each team scored per game is listed below: Team X: 11, 3, 0,

Gre4nikov [31]

Answer:

C. Team Y’s scores have a lower mean value.

Step-by-step explanation:

We are given that Two soccer teams play 8 games in their season. The number of goals each team scored per game is listed below:

Team X: 11, 3, 0, 0, 2, 0, 6, 4

Team Y: 4, 2, 0, 3, 2, 1, 6, 4

Firstly, we will calculate the mean, median, range and inter-quartile range for Team X;

Mean of Team X data is given by the following formula;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{11+ 3+ 0+ 0+ 2+ 0+ 6+ 4}{8}$ = $\frac{26}{8}$ = 3.25

So, the mean of Team X's scores is 3.25.

Now, for calculating the median; we have to arrange the data in ascending order and then observe that the number of observations (n) in the data is even or odd.

Team X: 0, 0, 0, 2, 3, 4, 6, 11

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

Here, the number of observations is even, i.e. n = 8.

So, Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(\frac{8}{2})^{th} \text{ obs.} +(\frac{8}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(4)^{th} \text{ obs.} +(5)^{th} \text{ obs.} }{2}$

= $\frac{2+3}{2}$ = 2.5

So, the median of Team X's score is 2.5.

Now, the range is calculated as the difference between the highest and the lowest value in our data.

Range = Highest value - Lowest value

= 11 - 0 = 11

So, the range of Team X's score is 11.

Now, the inter-quartile range of the data is given by;

Inter-quartile range = $Q_3-Q_1$

$Q_1=(\frac{n+1}{4} )^{th} \text{ obs.}$

= $(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(2.25 )^{th} \text{ obs.}$

$Q_1 = 2^{nd} \text{ obs.} + 0.25[ 3^{rd} \text{ obs.} -2^{nd} \text{ obs.} ]$

= 0 + 0.25[0 - 0] = 0

$Q_3=3(\frac{n+1}{4} )^{th} \text{ obs.}$

= $3(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(6.75 )^{th} \text{ obs.}$

$Q_3 = 6^{th} \text{ obs.} + 0.75[ 7^{th} \text{ obs.} -6^{th} \text{ obs.} ]$

= 4 + 0.75[6 - 4] = 5.5

So, the inter-quartile range of Team X's score is (5.5 - 0) = 5.5.

<u>Now, we will calculate the mean, median, range and inter-quartile range for Team Y;</u>

Mean of Team Y data is given by the following formula;

Mean, $\bar Y$ = $\frac{\sum Y}{n}$

= $\frac{4+ 2+ 0+ 3+ 2+ 1+ 6+ 4}{8}$ = $\frac{22}{8}$ = 2.75

So, the mean of Team Y's scores is 2.75.

Now, for calculating the median; we have to arrange the data in ascending order and then observe that the number of observations (n) in the data is even or odd.

Team Y: 0, 1, 2, 2, 3, 4, 4, 6

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

Here, the number of observations is even, i.e. n = 8.

So, Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(\frac{8}{2})^{th} \text{ obs.} +(\frac{8}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(4)^{th} \text{ obs.} +(5)^{th} \text{ obs.} }{2}$

= $\frac{2+3}{2}$ = 2.5

So, the median of Team Y's score is 2.5.

Now, the range is calculated as the difference between the highest and the lowest value in our data.

Range = Highest value - Lowest value

= 6 - 0 = 6

So, the range of Team Y's score is 6.

Now, the inter-quartile range of the data is given by;

Inter-quartile range = $Q_3-Q_1$

$Q_1=(\frac{n+1}{4} )^{th} \text{ obs.}$

= $(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(2.25 )^{th} \text{ obs.}$

$Q_1 = 2^{nd} \text{ obs.} + 0.25[ 3^{rd} \text{ obs.} -2^{nd} \text{ obs.} ]$

= 1 + 0.25[2 - 1] = 1.25

$Q_3=3(\frac{n+1}{4} )^{th} \text{ obs.}$

= $3(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(6.75 )^{th} \text{ obs.}$

$Q_3 = 6^{th} \text{ obs.} + 0.75[ 7^{th} \text{ obs.} -6^{th} \text{ obs.} ]$

= 4 + 0.75[4 - 4] = 4

So, the inter-quartile range of Team Y's score is (4 - 1.25) = 2.75.

Hence, the correct statement is:

C. Team Y’s scores have a lower mean value.

4 0

3 years ago

Given that у=6 cm and θ=15 °, work out x rounded to 1 decimal place.

Lubov Fominskaja [6]

Sin(15)=6/x
x=6/sin(15)
x=23.2°

7 0

2 years ago

Read 2 more answers

Out of the total respondents, the percentage of respondents from the 46–55 age group who rated the film excellent is %. write yo

Mrrafil [7]

Missing data:

Viewer's Age Group Excellent Good Average Poor Marginal Total

16–25 52 42 12 7 113

26–35 33 50 5 9 97

36–45 58 12 28 34 132

46–55 25 17 22 12 76

56 + 12 5 3 8 28

Marginal Total 180 126 70 70 446

A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.

<h3>How to determine the rating of the film from the 46–55 age group?</h3>

A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.

25/446 = 0.05605

0.05605 $*$ 100% = 5.605%

Out of the entire respondents, the percentage of respondents from the 46–55 age group who ranked the film excellent exists at 5.605%.

To learn more about data refer to:

brainly.com/question/4219149

#SPJ4

3 0

2 years ago

Consider the functions f(x) = 3x2, g(x)=1/3x , and h(x) = 3x. Which statements accurately compare the domain and range of the fu

Genrish500 [490]

Answer:

all of the functions have a unique range ⇒ answer 1

Step-by-step explanation:

* Lets revise how to find the domain and the range of the function

- The domain is all values of x that make the function defined

- The range is the set of all output values of a function

∵ f(x) = 3x²

- It is a quadratic function

- There is no values of x make this function undefined

∴ The domain of f(x) is all real numbers

- To find the range calculate the vertex of the function

∵ f(x) = ax² + bx + c

∵ f(x) = 3x²

∴ a = 3 , b = 0 , c = 0

∵ h = -b/2a

∴ h = 0/2(3) = 0/6 = 0

∵ k = f(h)

∴ k = f(0) = 3(0)² = 0

∴ The vertex of the cure is (0 , 0)

∵ k is the minimum value of the parabola

∴ The range of f(x) is all real numbers greater than or equal

to zero ⇒ (1)

∵ g(x) = 1/3x

- It is a rational function

- to find the values of x which make the function undefined equate

the denominator by 0

∵ 3x = 0 ⇒ divide both sides by 0

∴ x = 0

∴ The domain of g(x) is all real numbers except zero

∵ We can not put x = 0, then there is no value of g(x) at x = 0

∴ The range of the g(x) is all real number except zero ⇒ (2)

∵ h(x) = 3x

- It is a linear function

∵ There is no values of x make this function undefined

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is all real numbers ⇒ (3)

* From (1) , (2) , (3) the answer is

all of the functions have a unique range

# Look to the attached graph to more understand

The red graph is f(x)

The blue graph is g(x)

The green graph is h(x)

8 0

3 years ago

Read 2 more answers