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Pepsi [2]
3 years ago
9

The model represents an inequality what is the solution set for.the inequality

Mathematics
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

The correct answer to the following question will be "Set of values".

Step-by-step explanation:

  • A solution set or a set solution seems to be a set of beliefs as well as values that achieve the required unfairness. It appears to mean that almost every valuation throughout the characteristic equation would then accommodate the inequality and no further value satisfies this same inequality or disparity.

<u>For Example:</u>

Solve:

⇒  2x + 3 \leq  7

In the above example "x" is a natural number.

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Lucia deposits $44.60 into her bank account on Tuesday Morning. Tuesday afternoon, she withdraws to $26.30 and $21.30. Does Luis
dexar [7]

Answer:

Less than

Step-by-step explanation:

Using the data from the question, we can create the following equation to solve this...

44.60 - (26.30 + 21.30) = x

44.60 - (47.60) = x

-3 = x

As you can see Lucia withdrew more money than what she actually deposited which means that her account balance on Tuesday Night is less than what it was on Monday night before the initial deposit. This can all be seen using the above equation which is designed.

8 0
3 years ago
If A=(0,0) and B=(8,2), what is the length of AB
NeX [460]

Answer:

\boxed{\sf Distance_{AB}= 8.24 \ units }

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , <u>A(</u><u>0</u><u>,</u><u>0</u><u>)</u><u> </u>and <u>B(</u><u>8</u><u>,</u><u>2</u><u>)</u> . The distance between the two points can be found out using the<u> </u><u>Distance</u><u> Formula</u><u> </u>, which is ,

<em>Distance Formula:- </em>

\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}

Therefore on substituting the respective values ,we can find the Distance as ,

\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}

<u>Simpl</u><u>i</u><u>fy </u><u>the </u><u>brackets</u><u> </u><u>,</u>

\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}

Square the numbers inside the squareroot ,

\sf\longrightarrow Distance =\sqrt{ 64 + 4}

Add the numbers inside the squareroot ,

\sf\longrightarrow Distance = \sqrt{68}

Find the value of squareroot,

\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}

<u>Hence</u><u> the</u><u> </u><u>distance</u><u> between</u><u> the</u><u> two</u><u> points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>2</u><u>4</u><u> </u><u>units </u><u>.</u>

3 0
3 years ago
A team can row 40 km in 2 hours when rowing with the current, but only
dexar [7]
<h3>Answer:  14 km per hour</h3>

=====================================================

Work Shown:

x = rowing speed when there is no current

c = speed of the current

speeds are in km per hour

-----------

Going downstream, i.e. with the current:

x+c = faster speed since the current is pushing you

distance = rate*time

d = r*t

40 = (x+c)*2

x+c = 40/2

x+c = 20

c = 20-x

-----------

Going upstream, i.e. against the current:

x-c = slower speed since the current is working against you

d = r*t

16 = (x-c)*2

16 = 2x-2c

2x-2c = 16

2(x-c) = 16

x-c = 16/2

x-c = 8

x-(20-x) = 8 ... plug in c = 20-x

x-20+x = 8

2x-20 = 8

2x = 8+20

2x = 28

x = 28/2

x = 14 km per hour is the rowing speed when there is no current

Side note: the speed of the current is c = 20-x = 20-14 = 6 km per hour.

3 0
2 years ago
Can someone help me with this question
d1i1m1o1n [39]

Answer:

Angle 1 and angle 4 are congruent because all vertical angles are congruent. Angle 1 and angle 5 are congruent because corresponding angles are congruent. Idk the rest.

Step-by-step explanation:

7 0
3 years ago
Multiply each set of numbers and match it with it’s product
Fynjy0 [20]

Answer:

1. 1. (\frac{5}{16}) (-2) (-4) (\frac{-4}{5})= -2 \\2. (2\dfrac{3}{5}) (\frac{7}{9})=(\frac{91}{45})\\3. (\frac{2}{3})(-4)(9)= -24\\4. (\frac{-3}{4}) (\frac{7}{8})=(\frac{-21}{32})

Step-by-step explanation:

These are simple multiplication questions of fractions. We multiply numerator with numerators and denominators with denominators. If numerator and denominator is both divisible by same number we can divide them for simplification.

1. (\frac{5}{16}) (-2) (-4) (\frac{-4}{5})

=(\frac{-10}{16}) (-4) (\frac{-4}{5})\\=(\frac{40}{16}) (\frac{-4}{5})\\=(\frac{-160}{80}) \\dividing\,\, numerator\,\, and\,\, denominator\,\, by\,\, 80\,\,\\= -2

2. (2\dfrac{3}{5}) (\frac{7}{9})

Converting mixed form into fraction form,

=(\frac{13}{5})(\frac{7}{9})

Multiplying numerators with each other and denominators with each other

=(\frac{13*7}{5*9})\\=(\frac{91}{45})

3. (\frac{2}{3})(-4)(9)

Multiplying these terms with each other:

=(\frac{2*-4}{3})(9)\\=(\frac{-8}{3})(9)\\=(\frac{-8*9}{3})\\=(\frac{-72}{3})\\

Dividing numerator and denominator with 3

=-24 

4. (\frac{-3}{4}) (\frac{7}{8})\\=(\frac{-3}{4}) (\frac{7}{8})\\=(\frac{-3*7}{4*8})\\=(\frac{-21}{32})

4 0
3 years ago
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