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erma4kov [3.2K]
3 years ago
15

Rearrange w=3(2a+b)-4 to make a the subject

Mathematics
1 answer:
garik1379 [7]3 years ago
4 0

Answer:

w-6b+4/6

Step-by-step explanation:

To get the answer you have to first open the bracket which will give you w=6a+6b-4.You then take 6b-4 to the other side to meet w after this divide all by 6 to make a the subject of the formula.

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Which is the largest number?<br> ОА. 1.9x 106<br> ОВ. 2.5 x 105<br> Ос. 8.7 x 102<br> OD. 5.8 x 103
DanielleElmas [232]
C. 8.7 x 102

8.7 x 102= 887.4
Which is the largest product out of all the other equations.

Hope this helps!
4 0
3 years ago
Read 2 more answers
I need help with my quiz please help this is consuming me
Strike441 [17]

Answer:

30.62 ft^2

8 0
3 years ago
Pat needs to determine the height of a tree before cutting it down to be sure that it will not fall on a nearby fence. The angle
dem82 [27]

Answer:

229.23 feet.

Step-by-step explanation:

The pictorial representation of the problem is attached herewith.

Our goal is to determine the height, h of the tree in the right triangle given.

In Triangle BOH

Tan 60^0=\dfrac{h}{x}\\h=xTan 60^0

Similarly, In Triangle BOL

Tan 50^0=\dfrac{h}{x+60}\\h=(x+60)Tan 50^0

Equating the Value of h

xTan 60^0=(x+60)Tan 50^0\\xTan 60^0=xTan 50^0+60Tan 50^0\\xTan 60^0-xTan 50^0=60Tan 50^0\\x(Tan 60^0-Tan 50^0)=60Tan 50^0\\x=\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0} ft

Since we have found the value of x, we can now determine the height, h of the tree.

h=\left(\dfrac{60Tan 50^0}{Tan 60^0-Tan 50^0}\right)\cdotTan 60^0\\h=229.23 feet

The height of the tree is 229.23 feet.

5 0
3 years ago
Marti had of a pizza remaining after
o-na [289]
I think it is 1/2
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8 0
3 years ago
In this problem we will be dealing with the probability density function (pdf) associated with a continuous random variable, X.
konstantin123 [22]

Answer:

b)\ 0.568

Step-by-step explanation:

Given

f(x) = 6x(1- x);\ 0 \le x \le 1

Required

P(0.3 < x < 0.7)

From the question, we have:

P(a < x < b) = \int\limits^b_a {f(x)} \, dx

So, we have:

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx

Open bracket

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx

Integrate

P(0.3 < x < 0.7) =  \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}

P(0.3 < x < 0.7) =  3x^2 - 2x^3|\limits^{0.7}_{0.3}

Substitute 0.7 and 0.3 for x

P(0.3 < x < 0.7) =  (3*0.7^2 - 2*0.7^3) - (3*0.3^2 - 2*0.3^3)

Using a calculator, we have:

P(0.3 < x < 0.7) =  (0.784) - (0.216)

Remove brackets

P(0.3 < x < 0.7) =  0.784 - 0.216

P(0.3 < x < 0.7) =  0.568

3 0
3 years ago
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