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agasfer [191]
3 years ago
15

I need to know the answers to the 3 questions in there

Mathematics
1 answer:
lina2011 [118]3 years ago
3 0
What are the three question?
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Find the value of cos 0 , If sec 0 = 3/2 0 < 90
UNO [17]

Answer:

Step-by-step explanation:

cos theta is 2/3 because  cos means reciprocal of sec

7 0
3 years ago
Read 2 more answers
Use the x-intercept method to find all real solutions of the equation -9^3-72^2-96x+36=3x^3+x^2-3x+8
Vadim26 [7]

Answer:

 x ≈ 0.290640965127

Step-by-step explanation:

y subtracting the right side of the equation, we get a function that is zero at a real solution for x. The only x-intercept is at approximately 0.290640965127.

___

The graph shows the x-intercept to be 0.2906. The value above was obtained by Newton's method iteration. The roots of this cubic will all be irrational.

7 0
3 years ago
Solve. Show work please. Passing through (-4,-1) and (3,4)
kvasek [131]
What are you asking exactly
3 0
3 years ago
mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for
frez [133]

mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

<u>Step-by-step explanation:</u>

Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest​ . Let's find out:

Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.

⇒ \frac{8000(12)}{100}(x) +\frac{2000(8)}{100}(x) =5600

⇒ \frac{8000(12)+2000(8)}{100}(x) =5600

⇒ (80(12)+20(8))(x) =5600

⇒ (960+160)(x) =5600

⇒ (1020)(x) =5600

⇒ x =\frac{5600}{1020}

⇒ x =5.5

Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

6 0
3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
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