The answers to the questions
Use this rule: <em>(x^a)^b = x^ab</em>
3(x + 2)^3/5 + 2 = 27
Subtract 3 from both sides
3(x + 2)^3/5 = 27 - 3
Simplify 27 - 3 to 24
3(x + 2)^3/5 = 24
Divide both sides by 3
(x + 2)^3/5 = 24/3
Simplify 24/3 to 8
(x + 2)^3/5 = 8
Take the cube root of both sides
x + 2 = 3/5√8
Invert and multiply
x + 2 = 8^5/3
Calculate
x + 2 = 2^5
Simplify 2^5 to 32
x + 2 = 32
Subtract 2 from both sides
x = 32 - 2
Simplify 32 - 3 to 30
<u>x = 30</u>
Answer:
Step-by-step explanation:
First you add 4 on both sides
X^2=0
Then you take square on both sides
X=+- the square root of 4
Simplify that
X=plus or minus 2
The answer can be either -2 or +2 (which is just 2)
Answer:
161700 ways.
Step-by-step explanation:
The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
In this question:
3 transistors from a set of 100. So
So 161700 ways.
