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According to the question of the statement, we can conclude that
PQ = 2B
QR = 2B
PR = base = B
Perimeter = P = 105
P = PQ + QR + PR
105 = 2B + 2B + B
B = 21
<h2>PQ = 2B = 42</h2><h2>QR = 2B = 42</h2>
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1 answer:
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First of all, let's study each function:
Function A)
This is a quadratic function. This type of function is a second-degree polynomial function.
Function B)
<span>
</span>
This is an exponential function. This type of function is a non-algebraic function. It's also called <span>transcendental function.
</span>Function C)
<span>
</span>
It's a straight line with slope equal to 100 and without y-intercept.
Function D)
<span>
It's a cubic function. It's a third</span>-degree polynomial function.
So from the figure it is obvious that the function that grows at the fastest rate is the exponential function B). In fact, an exponential function always grows more quickly than a polynomial function.
Function A)
This is a quadratic function. This type of function is a second-degree polynomial function.
Function B)
</span>
This is an exponential function. This type of function is a non-algebraic function. It's also called <span>transcendental function.
</span>Function C)
<span>
It's a straight line with slope equal to 100 and without y-intercept.
Function D)
<span>
It's a cubic function. It's a third</span>-degree polynomial function.
So from the figure it is obvious that the function that grows at the fastest rate is the exponential function B). In fact, an exponential function always grows more quickly than a polynomial function.
Given:
A six-sided die is rolled two times.
To find:
The theoretical fractional probability that the first number is greater than the second number.
Solution:
If a six-sided die is rolled two times, then the total possible outcomes are 36.
S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
The outcomes where the first number is greater than the second number are
A = {(2,1), (3,1), (3,2), (4,1), (4,2), (4,3), (5,1), (5,2), (5,3), (5,4), (6,1), (6,2), (6,3), (6,4), (6,5)}
So, the favorable outcomes = 15.
Now, the theoretical fractional probability that the first number is greater than the second number is
Therefore, the required probability is .