Question

How do I solve this

Answer 1

This is a quadratic equation, so you have to factor it. 

I will show you how to factor this equation by using the quadratic formula because it is my favorite way of figuring these types of problems out.

Quad. Form: -b  +/- √b² - 4ac
                           -------------------
                                  2a

ax² + bx + c

a = 1
b = 10 
c = 25


   -10 +/- √(10)² - 4(1)(25)      -10 +/- √100 - 4(25)       -10 +/- √100 - 100
      ----------------------------- ⇒ ----------------------------- ⇒ ----------------------------
                   2(1)                                      2                                         2


-10 +/- √0          -10 +/- 0       -10 + 0       -10                          -10 - 0
---------------- ⇒  ------------- ⇒ ----------- = -------- = -5   AND    ---------- = -5
        2                     2                     2             2                                2



In this case, x can only equal -5, but in many quadratic formulas, there can be multiple solutions for x. 

Answer 2

Factor the 25 where they multiply to make 25 and add to make 10 so now it's (x+5)and (x+5) so x=-5 because x+5=0 solved