Think of the 13-ft length of the ladder as the hypotenuse of a right triangle. Represent the horiz. distance from foot of ladder to base of tree by x, or 5 ft.
Represent the vert. dist. from base of tree to top of ladder by y, which is unknown.
Then (13 ft)^2 = (5 ft)^2 + y^2, or
169 ft^2 = 25 ft^2 + y^2. This simplifies to y^2 = 144. Thus y = + 12 feeet.
Note: Please pay attention to your spelling: "lader i up agenst a tree" should be "the top of a 13-ft ladder is placed against a tree."
Answer:
1) Place the compass point at the vertex of the angle and open it to any width. Draw an arc that intersects of the sides of the angle.
2) Place the compass point at the one of the intersection points. Place the pencil at the other intersection point. This sets the compass with.
3) Draw an arc inside the angle.
4) Move the compass point to the intersection point on the other side of the angle being sure to keep the compass width the same. Draw a second arc inside the angle.
5) Make a point where the 2 arcs intersect the angle. Use a straight edge to draw a ray from the vertex of the angle through the point.
I always feel drawn to the number 2 for some reason because it is in the middle between 2 and four and usually when given an option to pick a number I never pick a number that they say. Personally I just feel drawn to pick the number 2 its a nice even number and perhaps could be lucky :)
Answer:
at t=0 the car has moved 0 feet, also you know it has a constant speed so you get the points:
P1:(0,0) therefore you know b, the y-intercept=0
P2:(8,840)
insert P2 into y=mx+b
840=8m+0
840/8=m
105=m
so the result is:
y=105x=105t=f(t)=d
Step-by-step explanation:
