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Anastaziya [24]
3 years ago
5

A school has 300 students. If the ratio of boys to girls is 31 to 44, how many girls are there in the school?

Mathematics
1 answer:
Shalnov [3]3 years ago
6 0

Answer:

176 girls

Step-by-step explanation:

31+44 = 75

300/75 = 4

4*44 = 176

176 girls in the school

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Sally has completed 1/3 of her shift; Jerry has completed 5/6 of his shift; David has finished 1/2 of his shift; Mona has 7/8 of
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Sally = 1/3
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Write an equation that illustrates a number with two decimal places multiplied by a number with one decimal place. The product h
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Step-by-step explanation:

Let the number with two decimal places be 1.23

Let the number with one decimal place be 4.5

Then 1.23 multiplied by 4.5

= 1.23 × 4.5

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An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
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Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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<h2>Answer:</h2>

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