Question

Two automobiles start together from the same place and travel along the same route. The first averages 40 miles

Answer 1

Answer:

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

The "speedier" car goes 55 mph * 5 hrs = 55*5 miles

The "slower" car goes 40mph * 5   hrs = 40*5 miles

The distance between them is

55  *5 - 40*5

Answer 2

Answer:

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

You are solving how much miles (further along) would the second car be after 5 hours.

The first car averages 40 miles per hour. 5 hours later, it will have averaged about 200 miles in 5 hours (40 x 5 = 200).

The second car averages 55 miles per hour. 5 hours later, it will have averaged about 275 miles in 5 hours (55 x 5 = 275)

Subtract: 275 - 200 = 75

The second car would have averaged 75 more miles than the first car.

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