Answer:
V= 160pi or V= 502.65
Step-by-step explanation:
V = pi × r^2 × h
V = pi × (4)^2 × 10
V = pi × 16 × 10
V= 160pi or V = 502.65
y=4/3x-5.
y=-5x+1
number 10
dy/dx =(dy/dt).(dt/dx)
now find
dy/dt=4t-1. , dt/dx=1
so : dy/dx=(4t-1).(1)
dy/dx= 4t-1 ,we have x=t-3-----> t=x+3
subtitute at t
dy/dx= 4(x+3)-1=4x+12-1= 4x+11
its a
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