Answer:
Yes, one of a rhombus's properties is that the diagonals bisect vertex angles.
Answers:
CB = 14
GF = 8
FB = 9
EF is parallel to CB
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Explanations:
Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14
For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.
FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length
EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.
Answer:
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Step-by-step explanation:
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Answer: fhesfuiewf fjjbeuihr jkfhur
Step-by-step explanation:
Answer:
72 in^2
Step-by-step explanation:
The area of the square in the middle is
A = s^2 = 6^2 = 36
The area of the triangle on the left is
A =1/2 bh = 1/2 ( 6*6) = 18
The area of the triangle on the right
A = 1/2 bh = 1/2(6*6) = 18
Add the areas together
36+18+18 = 72
