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2 years ago

Find the value of -20+ (-100)-(-100)+(-150)-300

Mathematics

2 answers:

ioda2 years ago

8 0

Answer:

- 470.

Step-by-step explanation:

-20+ (-100)-(-100)+(-150)-300

Distributing the negative over the parentheses (recall that <u>-* - = +</u> and <u>- * + = -</u>)

= -20 - 100 + 100 - 150 - 300

= 100 - 100 - 20 - 150 - 300

= 100 - 570

= - 470.

d1i1m1o1n [39]2 years ago

6 0

Answer:

=−470

Step-by-step explanation:

−20−100−(−100)−150−300

=−120−(−100)−150−300

=−20−150−300

=−170−300

=−470

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Light travels at the speed of approximately 3.0 × 108 meters per second. Find the time in minutes required for light to travel f

expeople1 [14]

Speed = distance / time => time = distance / speed
speed = 3x10^8 x 60 = 180x10^8 m per minute
time = 1.5x10^11/180x10^8 = 150x10^9/180x10^8 = 5/6x10 = 8,3 minutes

6 0

2 years ago

One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on

irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna = 237.08 ft

Step-by-step explanation:

The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°

distance from her position to the top of the building = 2475 ft

distance from her position to the top of the flag = 2615 ft

(a) How far away from the base of the building is the surveyor located?

using the SOHCAHTOA principle

cos 34° = c/2475

c = 0.8290375726 × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b = 0.5591929035 × 2475

b = 1384.0024361

b = 1384.00 ft

(c) What is the angle of elevation from the surveyor to the top of the antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ = 0.784665392

∅ = cos-1 0.784665392

∅ = 38.310258303

∅ = 38.31°

(d) How tall is the antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) = 0.6199159917 × 2615

(a + b) = 1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00 = 237.08031822 ft

Height of antenna = 237.08 ft

8 0

3 years ago

Can someone please help me with this question

Tanzania [10]

Answer:

B) [1, 4, 7]

Step-by-step explanation:

Substitute 0 in

f(0) = 3(0) + 1

Multiple

f(0) = 0 + 1

f(0) = 1

Substitute 1 in

f(1) = 3(1) + 1

f(1) = 3 + 1

f(1) = 4

Substitute 2 in

f(2) = 3(2) + 1

2 = 6 + 1

f(2) = 7

8 0

2 years ago

Read 2 more answers

Ive been at this for abt 30 min. help?

gregori [183]

Answer:

$1+\frac{-63}{x^2-1}$

Step-by-step explanation:

If you foil this equation you will get:

$\frac{(x+8)(x-8)}{(x+1)(x-1)}$

And by dividing it, you will get;

$1+\frac{-63}{x^2-1}$

That is your answer!

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3 years ago

Four golf balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the c

Andre45 [30]

Hello,
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5 0

3 years ago