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3 years ago

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Mathematics

1 answer:

REY [17]3 years ago

6 0

Answer:

Try to re write this question so I can help. I can not help without the answer choices

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An architect is designing a gym for a new elementary

Liono4ka [1.6K]

Answer:

Step-by-step explanation: 60x116=6960

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3 years ago

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HELP PLEASE 80 POINTS

alexgriva [62]

Answer:

x = 15/p
x = -3

Step-by-step explanation:

<h3>Given</h3>

4(px + 1)=64

Solve for x
Find x when p = -5

<h3>Solution</h3>

4(px + 1) = 64
4(px + 1)/4 = 64/4
px + 1 = 16
px = 15
x = 15/p

<u>When p = -5, substitute p:</u>

x = 15/p
x = 15/(-5) = -3

4 0

3 years ago

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Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .