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olga_2 [115]
3 years ago
5

Given the piecewise function shown below, select all of the statments that are true.

Mathematics
1 answer:
timurjin [86]3 years ago
8 0
The <span>given the piecewise function is :
</span>
f(x) = \[ \begin{cases} &#10;      2x & x \ \textless \  1 \\&#10;      5 & x=1 \\&#10;      x^2 & x\ \textgreater \ 1 &#10;   \end{cases}&#10;\]

To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25


To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4

To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4

To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
================================
So, the statements which are true:<span>
\framebox {B. f(2) = 4} \ \framebox {D. f(1) = 5}</span><span></span>
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Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 26, the length of A C is 10, and the leng
ExtremeBDS [4]

Answer:

<h2>The right option is twelve-fifths</h2>

Step-by-step explanation:

Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.

Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;

Tan (A) = opp/adj

Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;

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The right option is therefore twelve-fifths

7 0
3 years ago
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Match the equation below with the following graph.
Lemur [1.5K]

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The equation of the line in point-slope form is expressed as;

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Using the coordinates (0,4) and (-2, 0)

Slope = 0-4/-2-0

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2 years ago
Given: KLMN is a trapezoid m∠K = 90°, m∠N = 45° LK = LM = 10 Find: KN, Area of KLMN
Ilya [14]
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to A= \frac{LM+KN}{2} *MP= \frac{10+20}{2} *10=150 sq. units.


5 0
3 years ago
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