Answer:
310
Step-by-step explanation:
100+3=103
103+200=303
303+7=10
Answer:
<h2>
The right option is twelve-fifths</h2>
Step-by-step explanation:
Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.
Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;
Tan (A) = opp/adj
Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;
tan(A) = BC/AC
tan(A) = 24/10
tan(A) = 12/5
The right option is therefore twelve-fifths
Answer:
2x+4
Step-by-step explanation:
The equation of the line in point-slope form is expressed as;
y - y0 = m(x-x0)
Using the coordinates (0,4) and (-2, 0)
Slope = 0-4/-2-0
slope = -4/-2
slope = 2
Substitute m = 2 and the point (0,4) into the formula;
y - 4 = 2(x-0)
y - 4 = 2x
since y = 4 + 2x
y = 2(x+2)
Hence the required equation is 2x+4
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.