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2 years ago

How do I give a Brainliest to somebody?

Mathematics

2 answers:

Dominik [7]2 years ago

6 0

Answer:

there have to be at least two answers, then you have the option to mark brainliest by pressing the crown

Step-by-step explanation:

Hope this helps!

vlada-n [284]2 years ago

6 0

Answer:

Just click the crown above some ones answer when 2 people answer your question. You can only mark someone brainliest if you ask a question, not on other peoples questions.

Step-by-step explanation:

Have a great day and pls mark me brainliest ;)

#Equestrians

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Assume that the function f is a one-to-one function, (a) f(8) = 9, find f ^ -1 (9)

Annette [7]

(a) since we are given that f(8) = 9, the inverse of 9 is simply 8. Therefore, f^-1(9) = 8.

(b) Again, f is the inverse of f^-1, therefore, you simply switch numbers, and you get that f(-3) = -7.

8 0

3 years ago

A phone company charges 12 cents per minute of call. If Gerardo made a call that took 75 minutes using this plan, how much did h

sukhopar [10]

Answer:

900 cents, 9 dollars

Step-by-step explanation:

4 0

3 years ago

Need help with this problem

Zanzabum

Answer:

C. Priya needs to charge at least $21 per bracelet.

Step-by-step explanation:

$117b - 505 \ge 1952$

Add 505 to both sides.

$117b \ge 2457$

Divide both sides by 117.

$b \ge 21$

Answer: C. Priya needs to charge at least $21 per bracelet.

7 0

3 years ago

4x-11=3.2x+13. Write the lesser solution first. Round to the nearest tenth if needed

notsponge [240]

Answer:

The answer is (30, 109)

Step-by-step explanation:

In this problem we need to find the intersection point between the lines

y = 4x-11

and

y = 3.2x+13

We can easily solve this problem by plotting both lines in a graphing calculator and finding the intersection point.

Please see attached picture.

The answer is (30, 109)

8 0

4 years ago

What are the factors of x2 – 100?

I am Lyosha [343]

Answer:

(x-10)(x+10)

Step-by-step explanation:

Here, the given expression,

$x^2-100$

$=(x)^2-(10)^2$

By using the identity $a^2-b^2=(a+b)(a-b)$

$=(x+10)(x-10)$

$=(x-10)(x+10)$ ( By the commutative property )

Since, further factorization is not possible,

Hence, the factors of $x^2-100$ are,

$(x-10)(x+10)$

Second option is correct.

8 0

4 years ago