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Ilia_Sergeevich [38]
3 years ago
13

Find the number of real number solutions for the equation. x2 + 9x + 20 = 0

Mathematics
1 answer:
fiasKO [112]3 years ago
6 0

x^2 + 9x + 20 = 0 \\ x^2+4x+5x+20=0\\ x(x+4)+5(x+4)=0\\ (x+5)(x+4)=0\\ x=-5 \vee x=-4

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that’s the answers for them :), have a great day !! :)
5 0
2 years ago
Can anyone do this 3 questions please....
Colt1911 [192]

Answer:

23 ) 60 x raised to 3  , y raised 3  , z raised to 3

25 ) 12 p

Step-by-step explanation:

23 ) volume of a rectangular box = l ×b×h

       3x square y * 4y square * 5z square x

        60 x raised to 3

25 )  area of a square = side × side

        (3×4) p

          12 p


5 0
3 years ago
Mr. Omar assigns homework to his class and the homework requires students to
pychu [463]
Answer: no he is not correct
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7 0
2 years ago
Question Details
Sliva [168]

Answer:

Atomic mass unit-

It is represented by ‘amu’. It is equal to the quantity 1/12th mass of an atom of C-12.

Actual mass of one atom of C-12 = 1.9924 x 10-23 gm. = 1.9924 x 10-26 Kg.

1 amu = 1.9924 x 10 -23/12 = 1.66 x 10 -24 gm. = 1.66 x 10 -27 Kg.

Atomic mass of an element = mass of one atom of the element / 1 amu

Actual mass of an element = atomic mass of an element in amu x 1.66 x 10 -24 gm.

For ex-

Actual mass of hydrogen atom = 1.008 x 1.66 x 10 -24 gm. = 1.6736 x 10-24 gm.

Actual mass of oxygen atom = 16.00 x 1.66 x 10 -24 gm. = 2.656 x 10-23 gm.

Average Atomic weight (Mass)-

“The Average Atomic Masses of many elements are determined by multiplying the atomic mass of each isotope by its fractional abundance and adding these values and then dividing it by 100.”

Ex.- Naturally occurring carbon contains three isotopes – C12 (98.892 % abundance), C13 (1.108 % abundance), C14 (2 x 10-10 % abundance).The relative atomic masses of these isotopes are 12.000, 13.00335 and 14.00317 amu respectively.

Average atomic mass = % of I isotope x its atomic mass + % of II isotope x its atomic mass +% of III isotope x its atomic mass/100

= 12 x 98.892 + 13.00335 x 1.108 + 14.00317 x 2 x10-10 /100

Average atomic mass= 12.011 amu

Molar volume –

Molar volume of a substance is volume occupied by 1 mole of that substance .

Molar volume of solid or liquid = molar mass / density

Molar volume of ideal gas at 00C or 273 K and 1 atmosphere pressure is 22.4 litre.

Gram atomic mass(weight) or gram atom –

“Gram atomic mass(weight) of an element is the mass of Avogadro number ( 6.023 x 1023 ) of atoms of that elements in grams.”

Ex –

mass of 1 atom of oxygen = 16 amu = 16 x 1.66 x 10-24 gm

Mass of 6.023 x 1023 atoms of oxygen= 16 x 6.023 x 1023 x 1.66 x 10-24 = 16 gm.

Hence, Gram atomic weight of oxygen = 16 gm.

No. of gram atoms = mass of element in gm / atomic mass of element in gm.

7 0
3 years ago
Find the slope of the line y = 1/8x - 1.
konstantin123 [22]
The slope of the line is 1/8.

The slope is always attached to the x.

Hope this helps!!
6 0
3 years ago
Read 2 more answers
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