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Ilia_Sergeevich [38]
2 years ago
13

Find the number of real number solutions for the equation. x2 + 9x + 20 = 0

Mathematics
1 answer:
fiasKO [112]2 years ago
6 0

x^2 + 9x + 20 = 0 \\ x^2+4x+5x+20=0\\ x(x+4)+5(x+4)=0\\ (x+5)(x+4)=0\\ x=-5 \vee x=-4

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Average rate of change help!!
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Given that the function is f(x)=x^{3}-6 x^{2}+4 x+7

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<u>Value of f(x) when x = 0:</u>

Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

f(0)=0-0+0+7

f(0)=7

Thus, the value of f(0) is 7.

<u>Value of f(x) when x = 5:</u>

Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7

f(5)=125-150+20+7

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Thus, the value of f(5) is 2.

<u>Average rate of change:</u>

The average rate of change can be determined using the formula,

Rate \ of \ change=\frac{f(b)-f(a)}{b-a}

where a=0 and b=5

Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

Rate \ of \ change=\frac{2-7}{5-0}

Rate \ of \ change=\frac{-5}{5}

Rate \ of \ change=-1

Thus, the average rate of change over the interval 0 \leq x \leq 5 is -1.

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Answer:

Step-by-step explanation:

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I think y= -9/12x + .5
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Answer:

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8h=240

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