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Ira Lisetskai [31]
3 years ago
8

What is the 66th term of the arithmetic sequence -28, -45, -62

Mathematics
2 answers:
Rom4ik [11]3 years ago
7 0

Answer:

a(66) = -1133

Step-by-step explanation:

The common difference here is -17.  Note that -45 is equal to the previous value (-28), and that subtracting 17 from -28 yields -45.

Then the explicit equation of this arithmetic sequence is

a(n) = -28 - 17(n - 1)

and the 66th term is a(66) = -28 - 17(65), or a(66) = -1133

faust18 [17]3 years ago
4 0

Answer:-1133

Step-by-step explanation:

-28,-45,-62

First term=a=-28

Common difference=d=-45-(-28)

d=-45+28

d=-17

Using the formula

Tn=a + d x (n-1)

T66 is the 66th term

T66=-28 + (-17)(66 - 1)

T66=-28 + (-17)(65)

T66=-28 - 1105

T66=-1133

66th term=-1133

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