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TiliK225 [7]
3 years ago
13

I need help please.

Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0

Step-by-step explanation:

2(x - 7) = 3(x + 9)

2x - 14 = 3x + 27

2x - 3x = 27 + 14

-x = 41

x = - 41

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2 years ago
if we have a geometric series with u1 = 2.1 and r= 1.06, what would the least value of n be such that Sn &gt; 5543?
bulgar [2K]

Answer:

  88

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Write the expression for the sum in the relation you want.

  Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)

  Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)

The relation we want is ...

  Sn > 5543

  35(1.06^n -1) > 5543 . . . . substitute for Sn

  1.06^n -1 > 5543/35 . . . .  divide by 35

  1.06^n > 5578/35 . . . . . . add 1

  n·log(1.06) > log(5578/35) . . . take the log

  n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n

The least value of n such that Sn > 5543 is 88.

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