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3 years ago

Can someone help me pls :)

Mathematics

1 answer:

serg [7]3 years ago

4 0

Answer:

x=10

Step-by-step explanation:

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A 9-kilogram bag of sugar cost $27.54. what is the unit price ?

shusha [124]

Answer:

$3.06

Step-by-step explanation:

1 kg = $27.54

27.54/9 kilogram

4 0

4 years ago

6/8=y/16 how do you find the proportion of value y

Katarina [22]

You can set both fractions to have the same denominator by multiplying 6/8 (both the 6 and 8) by 2 to keep the value of the fraction, while turning the denominator to 16. So you get 12/16=y/16.
That means for the equation to be true y has to be 12.

Hope this helps!

4 0

4 years ago

Which equation below represents the inverse function B(a) , which takes the trapezoid's area as input and returns as output the

8090 [49]

A(b) = 12(b + 9) / 2
12(b + 9) = 2 A(b)
b + 9 = 2 A(b) / 12 = A(b) / 6
b = A(b)
----- - 9
6

B(a) = a
-- - 9
6

It's C

5 0

3 years ago

Read 2 more answers

Right triangle FHG is shown. The sine of angle F is 0.53. What is the cosine of Angle h ?

g100num [7]

<u>Given</u>:

Given that FGH is a right triangle. The sine of angle F is 0.53.

We need to determine the cosine of angle H.

<u>Cosine of angle H:</u>

Given that the sine of angle F is 0.53

This can be written as,

$sin F=0.53$

Applying the trigonometric ratio, we have;

$\frac{HG}{FH}=0.53$ ----- (1)

Now, we shall determine the value of cosine of angle H.

Let us apply the trigonometric ratio $cos \ \theta=\frac{adj}{hyp}$ , we get;

$cos \ H=\frac{HG}{FH}$ ----- (2)

Substituting the value from equation (1) in equation (2), we get;

$cos \ H=0.53$

Thus, the cosine of angle H is 0.53

6 0

3 years ago

The supplement of an angle is 50 less than 3 times its complement, find the measure of the angle

Lelechka [254]

Answer:

$20^{\circ}$ .

Step-by-step explanation:

Two angles are supplements of one another if their sum is $180^{\circ}$ .

Two angles are complements of one another if their sum is $90^{\circ}$ .

Let $x^{\circ}$ be the measure of the angle in question.

The supplement of this angle would be $(180 - x)^{\circ}$ .

The complement of this angle would be $(90 - x)^{\circ}$ .

According to the question:

$(180 - x) + 50 = 3\, (90 - x)$ .

Solve this equation for $x$ :

$x = 20$ .

Thus, this angle would measure should $20^{\circ}$ .

The supplement of this angle would measure $(180 - 20)^{\circ} = 160^{\circ}$ . The complement of this angle would measure $(90 - 20)^{\circ} = 70^{\circ}$ .

Three times the complement of this angle would be $3 \times 70^{\circ} = 210^{\circ}$ , which is indeed $50^{\circ}$ greater than the supplement of this angle.

8 0

3 years ago