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zloy xaker [14]
3 years ago
5

Can someone help me with this question? Plzz don’t guess if you don’t know. Ty!

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0

Answer: it’s not C or D if that’s helps

Step-by-step explanation:

podryga [215]3 years ago
7 0

Answer:

I would go with C since it makes the most sense to me.

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Please please please help me with this answer
Rasek [7]

x = number of packages he bought

y = number of popsicles in each package

Here are the two equations:

xy = 54

x = 3 + y

Using the substitution method, you can solve them to find x and y.

(3 + y)y = 54,

3y + y^2 = 54

y^2 + 3y - 54 = 0

Solve the quadriatic equation:

(y +9)(y - 6) = 0

y = -9, 6.

Plug y into: xy = 54

x(-9) = 54, x = -6.

x(6) = 54, x = 9.

So he bought 9 packages of popsicles, bc you can't bye -6 packages.

3 0
3 years ago
Which of these numbers is a solution to this problem: X is greater than 9?
Shtirlitz [24]
X = 12, because there is only one answer that has a number bigger than 9 :)
8 0
4 years ago
Given the function y=log3(x+2)-2. List the transformations
slava [35]

Answer:

Exponential transformation.

Step-by-step explanation:

y = log_3 (x + 3) - 2

To transform this into exponential, we have:

Adding 2 to both sides

y + 2 = log_3 (x + 3)

3^(y + 2) = x + 3

x = 3^(y + 2) - 3

4 0
3 years ago
Micheal has 5^(2) boxes. There are 5^1 of apples in each box. When empty, a box weighs 5^-2 kg. What is the total weight of boxe
Bond [772]

Answer:

5.4

Step-by-step explanation:

Juss took the test

7 0
3 years ago
The following data points represent the number of attendees at each of the dance events hosted by Cloy
Viktor [21]
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7),  9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.

5 0
3 years ago
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