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NeTakaya
4 years ago
11

CAN YALL HELPP PLZZZZ!!!!!!!

Mathematics
1 answer:
Nikolay [14]4 years ago
6 0

Answer:

D) 2p+14/p

Step-by-step explanation:

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5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is
AleksandrR [38]

Answer:

 \frac{16r^3}{3}

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

\int\limits^r_a {2(x^2+r^2 )} \, dx

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

\frac{16r^3}{3}

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

4 0
3 years ago
1-cos^2 A / sec^2 A - tan^2 A
tiny-mole [99]
I hope this helps you



✔cos^2A+sin^2A=1


✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

✔sin2A=2.sinA.cosA


secA=1/cosA


tgA=sinA/cosA


sin^2A/1/cos^2A-sin^2A/cos^2A


sin^2A.cos^2A/cos2A

2.sin^2A.cos^2A/cos2A


sin2A.2.sin2A/cos2A


tg2A.2.sin2A


6 0
3 years ago
six girls and four boys have entered the science fair. first, second, and third place awards are to be given out. what is the pr
Dafna1 [17]
Given:
6 girls
4 boys

Probability of 1 girl being chosen: 1/6
Probability of 1 boy being chosen: 1/4
Probability of another boy being chosen: 1/3

1/6 = 0.17 x 100% = 17%
1/4 = 0.25 x 100% = 25%
1/3 = 0.33 x 100% = 33%

17% + 25% + 33% = 75%

The probability that exactly one girl and two boys will receive awards is 75%.
7 0
4 years ago
Read 2 more answers
Max has 5.50. He has eight more quarters than he does nickels. He had four times as many dimes as he has nickels. How many quart
Oliga [24]

Answer:

<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>

Step-by-step explanation:

Givens

  • Max has $5.50.
  • He has eight more quarters than he does nickels.
  • He had four times as many dimes as he has nickels.

From these statements, we can deduce algebraical expressions to solve the problem. Let's call q quarters, n nickels and d dimes.

q=n+8 (8 more quarters than nickels)

d=4n (he has four times as many dimes as he has nickels).

0.25q+0.05n+0.10d=5.50 (Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).

Let's replace the first two expressions into the third equation

0.25(n+8)+0.05n+0.10(4n)=5.50\\0.25n+2+0.05n+0.40n=5.50\\0.70n=5.50-2\\n=\frac{3.50}{0.70}\\ n=5

There are 5 nickels.

Now, we use this value to find the number of quarters

q=5+8=13

There are 13 quarters.

Also, d=4(5)=20

There are 20 dimes.

Therefore, there are 13 quarters, 5 nickels and 20 dimes.

3 0
3 years ago
There are 32 red or blue marbles in a bag. The number of red marbles is 4 more than 3 times the number of blue marbles. Write an
eimsori [14]

Answer:

# red marbles = 25

# blue marbles = 7

Step-by-step explanation:

r + b = 32

r = 4 + 3b

substitute '4 + 3b' for 'r' in the 1st equation

4 + 3b + b = 32

4 + 4b = 32

4b = 28

b = 7

red = 32 - 7

r = 25

5 0
3 years ago
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