Answer:
Vamos a inventa tres multiplicaciones de seis factores en la que el resultado sea positivo, es decir un número mayor que cero, en la otra negativo, es decir, un número menor que cero y por último otra multiplicación que de como resultado el cero "0".
Primero recordemos que:
Los factores son los números que se multiplican.
Seis factores serían 6 números.
Multiplicación con resultado positivo, es decir mayor a 0:
2×3×4×2×1×5=240
Multiplicación con resultado negativo, es decir menor a 0:
-4×2×5×2×1×10= -400
Multiplicación con resultado cero:
2×4×6×7×11×0=0
Step-by-step explanation:
Brainliest please
Answer:
answer a. Because 16^2=256
4^2+ 4/15^2=16.01
16.01<256 . Therefore, it is acute-angled acute
<h2>
Automobile must travel at 96 mph to pass the truck in 4 seconds.</h2>
Step-by-step explanation:
Length of automobile = 16 feet = 4.88 m
Length of truck = 28 feet = 8.53 m
Speed of truck = 30 mph = 48 km/h = 13.33 m/s
Time in which automobile to pass truck = 4 s
Distance traveled by truck in 4 seconds = 4 x 13.33 = 53.33 m
Distance which need to cover by automobile in 4 seconds to pass truck is the sum of length of automobile, length of truck and distance traveled by truck in 4 seconds.
Distance which need to cover by automobile in 4 seconds = 4.88 + 8.53 + 53.33
Distance which need to cover by automobile in 4 seconds = 66.74 m
Distance = Speed x Time
66.74 = Speed x 4
Speed = 16.69 m/s = 60 km/h = 96 mph
Automobile must travel at 96 mph to pass the truck in 4 seconds.
Answer:
Step-by-step explanation:
y = 2x^2 - 12x +19 Put brackets around the 1st 2 terms. Take 2
y = 2(x^2 - 6x ) + 19 Take 1/2 of the 6 square it and add inside the brackets
y = 2(x^2 - 6 + (6/2)^2) +19 Subtract 2 *9 from the 19. Express 1st 3 terms as ( )^2
y = 2(x- 3)^2 + 19 - 18
y = 2(x - 3)^2 + 1
Answers
y intercept when x = 0 is y = 19
axis of symmetry x = 3
vertex: (3,1)
Graph
graph: red
axis of symmetry: blue
y intercept, vertex: green
Answer:
D
Step-by-step explanation:
This is because they are both mulitplied by two so they are still equivalent
