Answer:
The degree of fastness by which the water is rising is 210 seconds
Step-by-step explanation:
The volume of the trough when the water depth is 20 cm is first calculated
Volume of the trough (Trapezoidal Prism) = LH (A + B) × 0.5
Where L is the length of the trough, H is the height of the trough and A and B are parallel width of the top and bottom of the trough
Volume of the trough = 7 × 0.2 (0.3 + 0.7) × 0.5 = 0.7m³
The fastness at which the water is rising is = Volume ÷ water flow rate = 0.7 ÷ 0.2 = 3.5 min = 210 seconds
Given:
The radius, r=4x
The height,

To find the volume of the cone:
The volume of the cone formula is,

Substitute the values of r and h in the above formula we get,

Hence, the volume of the cone is

Thus, the correct option is option D.
Answer:
b
Step-by-step explanation:
Answer:
Step-by-step explanation:
