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Basile [38]
3 years ago
12

What is the number 100 before 2,589?

Mathematics
2 answers:
scoray [572]3 years ago
5 0
Uhh yes it is wayyy before 2,589 I believe
marshall27 [118]3 years ago
5 0

Answer:

2489

Step-by-step explanation:

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I absolutely suck in math so please just help me
agasfer [191]

All you have to do is substitute the values of x.

h(0) = |-3(0) + 5|

h(0) = |5|

h(0) = 5

The answer for h(0) is 5.

h(5) = |-3(5) +5|

h(5) = |-15 + 5|

h(5) = |-10|

h(5) = 10

The answer to h(5) is 10.

I hope this helps!

5 0
3 years ago
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
3 years ago
What's another name for a dog kennel?
ladessa [460]
Cage.....dog travel kit..... shelter.....pound.... it really depends on what you mean by dog kennel.
3 0
3 years ago
A software company is releasing one of their products on a CD. The manufacturer charges a $9700 setup fee and $1.25 per CD. Appr
Gre4nikov [31]

Answer:

  about 4312

Step-by-step explanation:

You want the total cost for n CDs to be 3.50n.

The manufacturer will charge you 9700+1.25n, so you want these to be equal:

  3.50n = 9700 +1.25n

  2.25n = 9700 . . . . . . . . subtract 1.25n

  n = 9700/2.25 ≈ 4311.111...

Producing 4312 CDs will make the cost per CD slightly less than $3.50.

____

Producing 4311 CDs will make the cost per CD be about $3.500058. Producing 4312 CDs will bring it down to $3.499536.

3 0
3 years ago
If you could help I would really appreciate it, but if not that’s fine. Thank you.
dolphi86 [110]

Answer:

3

Step-by-step explanation:

j(2) means that x equals 2...

the first inequality in the function says that x is greater than or equal to 2

the second inequality states that x is greater than 2(not equal to) and is less than or equal to 5

the third one states that x is greater than 5

x applies to the first inequality since we know that x can be equal to 2

Now, to the number before the if

there is a 3 before the if in the first inequality

This means that if x is greater than or equal to 2 the y or the function would equal 3

therefore, j(2) would equal 3

I hope this helps!!!

6 0
3 years ago
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