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Alika [10]
3 years ago
5

Need help ASAP !! Anyone get this question ?

Mathematics
2 answers:
Svetach [21]3 years ago
5 0

Answer:

4:12, 4 to 12, or 4/12

Step-by-step explanation:

this is so simple, first see how many down arrows are there

down arrows: 4

then count the total arrows

total: 12

down arrows to total arrows

4:12

OLEGan [10]3 years ago
3 0

Answer:

1:3

Step-by-step explanation:

Down arrows: 4 out of 12

4:12

1:3

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Answer:

The standard deviation of the price she will get is $8,371.58.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The variance of the uniform distribution is given by:

V = \frac{(b-a)^{2}}{12}

The standard deviation is the square root of the variance.

Uniformly distributed between $204,000 and $233,000

This means that a = 204000, b = 233000

So

V = \frac{(b-a)^{2}}{12} = \frac{(233000 - 204000)^{2}}{12} = 70,083,333.33

The standard deviation is the square root of the variance. So

S = \sqrt{70,083,333.33} = 8,371.58

The standard deviation of the price she will get is $8,371.58.

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John spends 1 hour making birthday cards. If each birthday card takes 3 minutes to make, how many birthday cards can John make?
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John can make 20 cards
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If you can solve all parts I will give brainliest (also give strategy)
Alexxx [7]

The Halloween conical hat, with given height, circular base and brim

extension has the following calculated parameters;

Part a. The slant height is <u>18.2 inches</u>

Part b. The volume of the cone is 37\frac{1}{2}  \cdot \pi in.³

Part c. The area of the brim, <em>A</em> = <u>36·π in.²</u>

Part d. The area of the brim is found by <u>subtracting the area of the base of the cone from the area covered by the perimeter of the brim</u>

Reasons:

Known parameters;

Height of the conical portion, h = 18 inches

Base circumference, C = 5·π inches

Part a. Slant height of the conical portion; Required

Solution:

The circumference of a circle, C = 2·π·r

Therefore;

r = \dfrac{C}{2 \cdot \pi}

Which gives;

r = \dfrac{5 \cdot \pi}{2 \cdot \pi} = \dfrac{5}{2} = 2.5

Radius, r = 2.5 inches

According to Pythagoras's theorem, we have; s² = r² + h²

Where;

s = The slant height of the cone

s² = 2.5² + 18² = 330.25

s = √(330.25) ≈ 18.2

  • The slant height, <em>s</em> ≈ <u>18.2 inches</u>

Part b. The measure in cubic inches of candy that exactly fills the conical portion of the hat is the volume of the cone.

Volume \ of \ a \ cone = \dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h

Therefore;

V = \dfrac{1}{3} \times \pi \times 2.5^2 \times  18 = 37\frac{1}{2}  \cdot \pi

  • The volume of the cone, V = 37\frac{1}{2}·π in.³

Part c. The extension of the brim from the base of the cone = 4 inches

The radius of the brim, R = Radius of the base of the cone + 4 inches

∴ <em>R</em> = 2.5 inches + 4 inches = 6.5 inches

Area of the brim, <em>A</em> = Area of the 6.5 inch circle - Area of the circular base of the cone

∴ A = π × 6.5² - π × 2.5² = 36·π

  • The area of the brim, <em>A</em> = <u>36·π in.²</u>

Part d. The procedure for solving the question in part c, is described as follows;

  • The area of the brim can be found by finding the entire area of the circle formed by the perimeter of the brim, then subtracting the area of the base of the cone from that area.

Learn more here:

brainly.com/question/17023854

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Rectangle JKLM is similar to rectangle WXYZ .
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This is what I am supposed to do, I’m confused on what to do on 3,4, and 5. PLEASE HELP ASAP!!!!!! 30 POINTS!!!!!
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Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

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Using (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 3, 6)

m = \frac{6-0}{-3-0} = \frac{6}{-3} = - 2

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y = - 2x ← equation of line

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let (x₁, y₁ ) = (6, 0) and (x₂, y₂ ) = (0, 3)

m = \frac{3-0}{0-6} = \frac{3}{-6} = - \frac{1}{2}

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = - \frac{1}{2} x + 3 ← equation of line

5

let (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (-2, - 3)

m = \frac{-3-3}{-2-0} = \frac{-6}{-2} = 3

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = 3x + 3 ← equation of line

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