Tony rounded each of the numbers 1,600 and 1,483 to the nearest thousand. Which choice correctly compares the rounded numbers
2 answers:
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Answer:
There is a 95% confidence that the sample has a mean between 158.92 pounds and 171.48 pounds
Step-by-step explanation:
Given that mean (μ) = 165.2 pounds, standard deviation (σ) = 12.4 pounds, sample size (n) = 15 crates. Confidence (C) = 95% = 0.95
α = 1 - C = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025
The z score of α/2 corresponds to the z score of 0.475 (0.5 - 0.025) which is 1.96.
The margin of error (E) is given by:
The confidence interval = μ ± E = 165.2 ± 6.28 = (158.92, 171.48)
The confidence interval is between 158.92 pounds and 171.48 pounds. There is a 95% confidence that the sample has a mean between 158.92 pounds and 171.48 pounds
Answer:
The present age of Sam is 20 years .
Step-by-step explanation:
Given as :
Let The age of John = J years
Let The age of Sam = S years
∵ Sam is 12 years older than John
so, The age of Sam = 12 + The age of John
i.e S = 12 + J .....1
<u>Again</u>
Before 5 years ago
The age of Sam = 5 times age of John
So, (S - 5) = 5 × (J - 5)
Or, S - 5 = 5 J - 25
Or, 5 J - S = 25 - 5
Or, 5 J - S = 20 .........2
Solving eq 1 and eq 2
[5 J - (12 + J)] = 20
Or, 5 J - 12 - J = 20
Or, 4 J = 20 + 12
Or, 4 J = 32
∴ J =
i.e J = 8 years
So, The age of John = J = 8 years
Put The value of J into eq 1
∵ S = 12 + J
So, S = 12 + 8
i.e S = 20 years
So, The present age of Sam = S = 20 years .
Hence, The present age of Sam is 20 years . Answer