Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Is 37% Ran to hide then 63% refuse to hide
63/2520= 37/X
63x= 93240
Divide by 63
X= 1480 Ran to hide
2520+1480=4,000 total --------------
4,000 people lived in the forest
Answer:
Step-by-step explanation:
If student ticket = 215 then 215 x 3 = 645$
Remaining tickets = 522 - 215 = 307
So adult tickets = 307 x 4 = 1228$
Total amount = 1228 + 645 = $1873
