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3 years ago

Choose each number that shows 1/2 % as an equivalent fraction, decimal, or percent. Select all that apply.

Mathematics

2 answers:

stepladder [879]3 years ago

7 0

Answer:

(1/2)% = 0.5% =0.5/100 = 0.005

=> Option E is correct.

Hope this helps!

Ostrovityanka [42]3 years ago

6 0

Answer:

Step-by-step explanation:

1/2% is .5% = .5/100 = .005

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19x+15y=-6 changed into slope intercept form.

attashe74 [19]

Answer:

y = - $\frac{19}{15}$ x - $\frac{2}{5}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

19x + 15y = - 6 ( subtract 19x from both sides )

15y = - 19x - 6 ( divide all terms by 15 )

y = - $\frac{19}{15}$ x - $\frac{6}{15}$ , that is

y = - $\frac{19}{15}$ x - $\frac{2}{5}$ ← in slope- intercept form

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4 years ago

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Liz Williams claims to have psychic abilities and predict the future. Anderson Cooper, a CNN personality plans to test her in hi

Katena32 [7]

Answer:

b. Because the probability of being 15 or more correct is 0.0207, it is likely that she is just guessing at the questions.

Step-by-step explanation:

-This is a binomial probability distribution with p=0.5, n=20 and x=15.

The function is expressed as:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}$

We calculate the probability of guessing 15 or more correctly:

$P(X\geq 15)=1-P(X$

The probability of passing, guessing 15+ correctly, is 0.0207. This probability is very low and it is it is likely that she is just guessing at the questions

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3 years ago

Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

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Marysya12 [62]

the answer is d (i think) because anything aboveboard .90, whether it is positive or negative

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