Answer: rate of train A = 120 km/h
rate of train B = 101 km/h
Step-by-step explanation:
Let x = the speed of train A
Let y = the speed of train B
One train travels 19 km/h slower than the other. Let train B be the slower train. Therefore,
x = y + 19 - - - - - - - - - -1
Recall
Speed = distance/time
Distance = speed × time
If they meet in 3 hours, it means that train A has travelled a distance of
x × 3 = 3x km
And train B has travelled a distance of y × 3 = 3y km
Train A and Train B were 663 kilometers apart when they left their respective destinations. They left at the same time and travelled towards each other. This means that if they meet in 3hours time, they must have covered a total of 663 km. Therefore,
3x + 3y = 663 - - - - - - - - - 2
Substituting x = y + 19 into equation 2, it becomes
3(y + 19) + 3y = 663
3y + 57 + 3y = 663
6y + 57 = 663
6y = 663 - 57 = 606
y = 606/6 = 101 km/h
x = y + 19 = 101 + 19
x = 120 km/h
The slope of the line is 4/3
A b c , d e f
Each letter represents a place value.
a = hundred thousands
b = ten thousands
c = thousands
d = hundreds
e = tens
f = ones
a number that has a double the number of tens as ones.
a b c, d ΔΔ Δ
and three times a number of thousands as hundreds
a b ∞∞∞ , ∞ ΔΔ Δ
The number would be: 3,121
Answer:
2/4 and 1/2
Step-by-step explanation:
I'm not sure if this is what you meant? i hope this helps anyway though!
Given:
Principal value = $8,008
Rate of interest = 2% compounded 6 times per year.
Time = 16 years
To find:
The account balance after 16 years.
Solution:
The formula for amount is:
Where, P is principal, r is the rate of interest, n is the number of times interest compounded in an year and t is the number of years.
Putting 
in the above formula, we get
Therefore, the account balance after 16 years is $11022.17.
