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3 years ago

Could I have help on B please?

Mathematics

2 answers:

djyliett [7]3 years ago

7 0

a->So the value of X is 80 degree.

b-> Reason: Corresponding angles are equal.

Look at the attached picture

Hope it will help you...

Good luck on your assignment

~pragya

adelina 88 [10]3 years ago

6 0

Answer:

Step-by-step explanation:

I remember studying this but forgot the terminology, but basically the line adds up to 180. I believe it was called Adjacent lines or something, but I don't remember. Hope this sparks your memory :)

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Given the function, f (x) = sq3x+3+3, choose the correct transformation.

iren2701 [21]

Answer:

Step-by-step explanation:

First, let's start from the parent function. The parent function is:

$f(x)=\sqrt{x}$

The possible transformations are so:

$f(x)=a\sqrt{bx-c} +d$ ,

where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.

From the given equation, we can see that a=1 (so no change), b=3, c=-3 (negative 3), and d=3.

Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the left (because it's negative), and a vertical shift of 3 upwards (because it's positive).

7 0

3 years ago

I need help -HOMEWORK

sladkih [1.3K]

20 cm^2
Imagine two of the as squares and then have them

8 0

3 years ago

Which of the following points would be a solution to this system of linear inequalities?

pychu [463]

Let's plug in both x and y values in the equation and check if the inequality is true...

$\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}$

$(4,1) \\ y \leqslant x + 1 \\ y < - \frac{x}{2} - 1$

Substitute x as 4 and y as 1

$1 \leqslant 4 + 1 \\ 1 < - \frac{4}{2} - 1$

$0 \leqslant 4 + 1 \\ 1 < - 2 - 1$

$0 \leqslant 5 \\ 1 < - 3$

This is not a solution because both are not true, Only one equation is giving true as answer which is not correct!~

$\purple{ \rule{300pt}{3pt}}$

$(0, - 3) \\ y \leqslant x + 1 \\ y < - \frac{x}{2} - 1$

Substitute x as 0 and y as -3

$- 3 \leqslant 0 + 1 \\ - 3 < - \frac{0}{2} - 1$

$- 3 \leqslant 1 \\ - 3 < - 0 - 1$

$- 3 \leqslant 1 \\ - 3 < - 1$

This is a solution because both are true, Both the equations are true which means the ordered pair is a solution!~

Thus, Option B (0,-3) is the correct choice....

6 0

3 years ago

Triangle PQR is similar to triangle KLM.

damaskus [11]

Answer: I think it’s b

Step-by-step explanation:

8 0

3 years ago

Find the solution to the given equation if the replacement set is {6, 9,15,16}.

Alexxandr [17]

They gave you a set of numbers that you replace the variable x in the equation to see if it gives a correct answer so just do exactly that.

6 + 2x = 24
6 + 2(6) = 24
6 + 12 = 24
18 = 24 so incorrect. both sides are not equal to each other.

6 + 2x = 24
6 + 2(9) = 24
6 + 18 = 24
24 = 24 so correct. both sides are equal to each other.

6 + 2x = 24
6 + 2(15) = 24
6 + 30 = 24
36 = 24 so incorrect. both sides are not equal to each other.

6 + 2x = 24
6 + 2(16) = 24
6 + 32 = 24
38 = 24 so incorrect. both sides are not equal to each other.

so your answer is b) 9

hope this helps, God bless!

6 0

3 years ago

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