Question

Given the function, f (x) = sq3x+3+3, choose the correct transformation.

Answer 1

Answer:

B.

Step-by-step explanation:

First, let's start from the parent function. The parent function is:

$f(x)=\sqrt{x}$

The possible transformations are so:

$f(x)=a\sqrt{bx-c} +d$,

where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.

From the given equation, we can see that a=1 (so no change), b=3, c=-3 (negative 3), and d=3.

Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the left (because it's negative), and a vertical shift of 3 upwards (because it's positive).