The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:
Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
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Answer:
n = 70
Step-by-step explanation:
14 * x < 80
x = 6 won't work
14 * 6 = 84 which beyond the boundry.
14 * 5 = 70 which is less than 80 and is divisible by 14
14 * 3 = 42
70 does not have a 3 in it.
So the largest number that has 14 in it and is less than 80 is 70
Area is the length times the width.
When you know the area and one of the dimensions, divide the area by the known dimension to find the other one.
133 / 11 = 12.09
The room needs to be at least 12.09 feet wide. ( round answer if needed).
Answer:
The answer rounded to the nearest percent is 19%.
Step-by-step explanation:
The formula for percent change is this:
((y2 - y1) / y1)*100
Let y1 be the first value (595) and let y2 be the second (708).
((702 - 595) / 595)*100
702 - 595 is 107 and 107/595 is approximately 0.188, multiplied by 100 is 18.8, which is rounded to 19%.
That is our solution.
<em>And that's an awfully small amount of rent to pay (at least in California).</em>
