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Sphinxa [80]
3 years ago
10

An equation of the line through the points (-2,5) and (3,-4) is??

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0
A is the right answer
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One week you tell 3 of your friends a secret. The next week, each of them tells 3 people the secret and the next week each of th
Ulleksa [173]
81 people  will know the secret by week 4
4 0
3 years ago
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An automobile insurance company issues a one-year policy with a deductible of 500. The probability is 0.8 that the insured autom
Effectus [21]

Answer:

y₀.₉₅ = 3659

Step-by-step explanation:

P( no accident ) = 0.8

P( one accident ) = 0

deductible = 500

mean = 3000

<u>Determine the 95th percentile of the insurance company payout </u>

Assuming : y =company payout , x =amount of loss incurred due to accident

Then :

P( x < 500 ) = 0.2 ( 1 - e^-500/3000)

                   = 0.2 ( 1 - e^-1/6 )

95th percentile =

= P( y < y₀.₉₅  ) 0.95

  P( y = 0 ) = 0.8 + 0.2 ( 1 - e^-1/6 ) = 0.8307

attached below is the remainder of the solution

5 0
3 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
3 years ago
Which statement correctly compares the mean number of students for the data in the plots?
satela [25.4K]

Answer:

<em><u>"There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."</u></em>

Step-by-step explanation:

We need to compute the mean for each.

<u>Poplar Middle School:</u>

Lets list the numbers

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

The average is sum of all divided by number of numbers, that will be:

435/20 = 21.75

<u>Oak Middle School:</u>

The numbers are:

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

The average is sum divided by number of numbers, that will be:

483/20 = 24.15

The difference in mean is:

24.15 - 21.75 = 2.4

We can say, that is about 2 more students in Oak Middle School, correct answer choice is "2nd answer choice" - <em><u>"There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."</u></em>

7 0
3 years ago
5c-15, what is the coefficient of the variable
erik [133]
5 is the coefficient 
5 0
3 years ago
Read 2 more answers
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