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deff fn [24]
3 years ago
14

If x = 4 and y = 7 , evaluate the following expression: 3(3y - 4x)

Mathematics
2 answers:
Alex Ar [27]3 years ago
4 0

Answer:

The answer is 15

Step-by-step explanation:

The answer is 15 because I used the order of operations. So, first I calculated the paranthesis. Then I multiplied left and right and I got 15.

zhenek [66]3 years ago
3 0

Answer:

the answer is 47

Step-by-step explanation:

you have to look at the y as 7 plug the 7 in the parentheses on the left side of the minus sign and you get 63. Now look at the 4x. X is now replaced with 4. 4 times 4 is 16. 63 minus 16 is 47.

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Practice using graphs of equivalent ratios. On a coordinate plane, point (2, 3) is plotted.A 2-column table with 3 rows. Column
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Answer:

2

Step-by-step explanation:

if you multiply 2 by 3=6

  1. 2×2=4
  2. 3×3=9

8 0
2 years ago
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Simplify the expressions by combining like terms<br><br> 10r - 5r + 3r - 8r
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Answer:

0

Step-by-step explanation:

Combine like terms, perform the operations with the coefficients of the variable, then write the variable.

10r - 5r + 3r - 8r

= 5r + 3r - 8r

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2 years ago
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8 0
3 years ago
If ∠A and ∠B are complementary, find the value of x given that ∠A=3x-2 and ∠B=x+12
xxMikexx [17]

Answer:

x=20 degrees

Step-by-step explanation:

complementary means the angles equal 90 degrees

so ∠A+∠B=90 degrees

∠A=3x-2 and ∠B=x+12

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6 0
2 years ago
How would the sum of cubes formula be used to factor x3y3 + 343? Explain the process. Do not write the factorization.
Svetllana [295]

Answer:

Given : Expression -x^3y^3+343

To find : How would the sum of cubes formula be used to factor given expression? Explain the process. Do not write the factorization.

Solution :

The formula of sum of cubes is,

a^3+b^3=\left(a+b\right)\left(a^2-ab+b^2\right)

First we convert the given expression in a^3+b^3

x^3y^3+343

Apply exponent rule : a^mb^m=(ab)^m

x^3y^3=(xy)^3

Rewrite 343=7^3

Therefore, x^3y^3+343  could be written as =\left(xy\right)^3+7^3

On comparison with the formula,

a=xy , b=7

\left(xy\right)^3+7^3=(xy+7)(xy^2-xy(7)+7^2)

\left(xy\right)^3+7^3=(xy+7)((xy)^2-7xy+49)            

5 0
3 years ago
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