Set up an equation and solve, or find a common sequence.
We can set up an equation like so, using x = 1 as a base:
x(number) + (another number) = y
translate to:
1(x) + (number) = 5
The common difference is 2 for each y value, so let's use that as a multiplier:
1(2) + number = y
2 + x = 5
x = 3
So lets move up a step:
x = 2 and y = 7
We use 2 as our multiplier and 3 as our adder:
2(x) + 3 = y
2(2) + 3 = 7
4 + 3 = 7
Lets try one more case :
x = 4 and y = 11
2(4) + 3 = 11
8 + 3 = 11
11 = 11
For the given quadratic equation we only have a maximum at y = 18.
<h3>
How to find the extrema of the given function?</h3>
Here we have:

Notice that this is a quadratic equation of negative leading coefficient.
Then we have a maximum at the vertex, and both arms tend to negative infinity as x tends to infinity or negative infinity.
The vertex is at:
x = -(-4)/(2*(-2)) = -1
The maximum is:

If you want to learn more about quadratic equations:
brainly.com/question/1214333
#SPJ1
Just plug in the numbers for the variables

Does this help?
Answer:
Doctor 1's average is 12 while doctor 2 is 16
Step-by-step explanation:
doctor 1:
20+22+29+15=17=18+1+1+2+3+7+9=144/12=12
doctor 2: 35+20+20+22+23+26+13+17+2+2+3+9=192/12=16