Question

Icated (Q#1-4). 2. Solve by substitution; x+3y + 4) 3x - 5y = 8 3 (3x+4) aytla

Answer 1

Answer:

See explanation

Step-by-step explanation:

Assuming your system is:

$x + 3y = 4$

$3x - 5y = 8$

Then make x the subject in the first equation to get:

$x = 4 - 3y$

Put this equation into the second equation to get:

$3(4 - 3y) - 5y = 8$

$12 - 9y - 5y = 8$

$- 9y - 5y = 8 - 12$

$-14y = - 4$

$y = \frac{ - 4}{ - 14} = \frac{2}{7}$

This means that:

$x = 4 - 3 \times \frac{2}{7}$

$x = 4 - \frac{6}{7} = \frac{22}{7}$