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MA_775_DIABLO [31]
3 years ago
11

A drawer contain pens , 14 blue pens and 8 black pens , 14 silver paper clips , and 16 white paper clips . If you randomly selec

t a pen and paper clip from the drawer , what is the probability that you select a red pen and white paper clip
Mathematics
1 answer:
vichka [17]3 years ago
4 0

Step-by-step explanation:

Total pens = 22

Total clips = 30

Probability of red pen = 0

Because there are no red pens

Probability of white clip = 16/30 = 8/15

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For all functions of the form f(x) = ax2 + bx + c, which is true when b = 0?
Klio2033 [76]
When b=0
f(x)=ax^2+c

test each
A. with x^2-1, A is false
B. with -x^2-1, B is false
C. cannot find contradiction
D. the axis is actually x=0, 0 is nithere positive nor negative, false


answer is C

7 0
4 years ago
Read 2 more answers
The volume of a cone is 763.02. the radius and height of the cone are equal. What is the radius of the cone?
LUCKY_DIMON [66]

Answer:

The radius of the cone is 9cm

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, a cone

The volume of a cone is expressed as

V=1/3(πr²h)

We were told that the radius r and the height h are equal

I.e r=h

Substituting h=r in the formula we have

V= 1/3(πr²*r)

V =1/3(πr³)

To find the radius r let us substitute our given 763.02cm³ (note we assume unit in cm)

763.02= 1/3(3.142r³)

763.02= (3.142r³)/3

763.02*3=3.142r³

2289.06=3.142r³

r³=2289.06/3.142

r³= 728.54

r= ³√728.54

r= 8.99cm

≈r= 9cm

3 0
3 years ago
Clarissas team collects m magazines for the recycling drive JoAnn team collects 3 times as many
WITCHER [35]

Answer: Clanssa’s team collects m magazines for the recycling drive. JoAnn’s team collects 3 times as many magazines as Clarissa’s team. JoAnn’s team collects a total of 654 magazines.​

6 0
3 years ago
the length of a rectangle is 2 inches less than twice its width. If the perimeter of the rectangle is 74 inches, what is the are
schepotkina [342]
If the width is w and the length is l, then 2w-2=l and 2w+2l=72 (using the perimeter equation). Plugging 2w-2 in for l, we get 2w+(2w-2)*2=72 and 6w-4=72. Adding 4 to both sides, we get 6w=76. After that, we divide both sides by 6 to get 74/6=w. Since l=2w-2=136/6, we get (136/6)(74/6)=656.75=area
5 0
3 years ago
Find the number of steel ball bearings, each of diameter 0.7 cm, that can be made from 1kg of steel, given that 1cm cubed of ste
dimulka [17.4K]

Answer:

Ball Bearing Volume = (4 / 3) * PI * radius ^3

Volume = (4 / 3) * 3.14159265 * (.35)^3

Volume = (4 / 3) * 3.14159265 * 0.042875

Volume = 0.17959438 cc

1 cc of steel = 7.8 g

Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc

1 kg = 128.205 cc

Number of ball bearings we can make = 128.205 / 0.17959438

Equals 713.86

Step-by-step explanation:

7 0
3 years ago
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